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vovikov84 [41]
3 years ago
11

Identify the initial amount a and the growth factor b in the exponential function.f(t)=1.4^t

Mathematics
1 answer:
vaieri [72.5K]3 years ago
6 0
Initial amount is when no change has happened or when t=0
that iniital amoun tis 1
the growth factor
welll, it grows by 40% each time of previous times

I would say growth factor of 1.4


f(x)=a(b)^t
f(t)=1(1.4)^t
initial amount is 1
grouth factor is 1.4
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Answer:

show the graph .

Step-by-step explanation:

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3 years ago
16 feet perimeter 5 feet long what is the width
miskamm [114]
P=2L+2W
L=Length
W=Width
P=Perimeter=16
So you have:
16=2×5+2w
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16=10+2w
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3 years ago
Let Y be a random variable with a density function given by
Neporo4naja [7]

From the given density function we find the distribution function,

F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y

(a)

F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)

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\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}

(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

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(c)

F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

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5 0
3 years ago
A tree planted today has a height of 5 feet and grows one foot each month.
sammy [17]

Answer:

Liner function

x = 5 + n

Step-by-step explanation:

Given:

Height of tree = 5 ft

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Find:

Equation:

Computation:

Assume;

New height of tree x

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3 0
3 years ago
Please answer this question, I will mark brainlest
adoni [48]

Answer:

B: 12

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Number of patches = 12

hope it helps

please mark me as brainliest

5 0
2 years ago
Read 2 more answers
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