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3 years ago

Identify the initial amount a and the growth factor b in the exponential function.f(t)=1.4^t

1 answer:

6 0

Initial amount is when no change has happened or when t=0
that iniital amoun tis 1
the growth factor
welll, it grows by 40% each time of previous times

I would say growth factor of 1.4

f(x)=a(b)^t
f(t)=1(1.4)^t
initial amount is 1
grouth factor is 1.4

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The distance from Rodney's house to the park is 100 meters. If he walks to the park and back to his house, how far will he have

konstantin123 [22]

Answer:

c. 20,000cm

Step-by-step explanation:

from is house to the park is 100m

from the park back to his house is another 100m

100m+100m=200m

1m = 100cm

200m = xcm

cross multiply

xcm = 200×100

xcm= 20,000cm

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3 years ago

What is 12 and 19 /20 as a decimal?

-BARSIC- [3]

12.95

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2 years ago

Read 2 more answers

You know that the Customer Acquisition Cost is the cost associated with convincing a customer to buy a good or service. It inclu

kozerog [31]

Answer:

The Customer Acquisition Cost for each customer in demographic group 1

The correct option is c

The Customer Acquisition Cost for Group 2

The correct option is b

Step-by-step explanation:

From the question we are told that

The marketing expenses per month for targeting the first group is $E = \$ 30,000$

The marketing expenses per month for targeting the second group is $F = \$ 60,000$

The number of customers for the demography of group 1 that will be attracted is N = 1000

The number of customers for the demography of group 2 that will be attracted is M = 1500

Generally the customer acquisition cost for group 1 is

$K = \frac{E}{ N}$

=> $K = \frac{30000}{ 1000}$

=> $K = \$ 30$

Generally the customer acquisition cost for group 2 is

$Z = \frac{F}{ M}$

=> $Z = \frac{60000}{ 1500}$

=> $Z = \$ 40$

8 0

3 years ago

How to solve <img src="https://tex.z-dn.net/?f=log_%7By%7D%285y%29%20%3D%202" id="TexFormula1" title="log_{y}(5y) = 2" alt="log_

Natalija [7]

Answer:

y = 5

Step-by-step explanation:

Expand the logarithm:

$\log_y{(5)}+\log_y{(y)}=2\\\\\dfrac{\log{(5)}}{\log{(y)}}+1=2 \quad\text{change of base formula}\\\\\dfrac{\log{(5)}}{\log{(y)}}=1 \quad\text{subtract 1}\\\\\log{(5)}=\log{(y)} \quad\text{multiply by log(y)}\\\\5=y \quad\text{take the anti-log}$

_____

You can also take the antilog first:

5y = y²

y(y -5) = 0 . . . . . subtract 5y, factor

y = 0 or 5 . . . . . y=0 is not a viable solution, so y=5.

5 0

3 years ago

Find the product of (x^2+2x-3)(4x^2-5x+6)

Evgesh-ka [11]

Answer:

$x^{4}$ + 3x³ - 16x² + 27x - 18

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

x²(4x² - 5x + 6) + 2x(4x² - 5x + 6) - 3(4x² - 5x + 6)

Distribute all 3 parenthesis

= 4 $x^{4}$ - 5x³ + 6x² + 8x³ - 10x² + 12x - 12x² + 15x - 18

Collecting like terms

= 4 $x^{4}$ + 3x³ - 16x² + 27x - 18

5 0

3 years ago