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zzz [600]
4 years ago
9

Jacob invested $300 in a savings account and earned $81 in interest at the end of 9 years. What was the interest rate?

Mathematics
1 answer:
ollegr [7]4 years ago
8 0
R = (1/t)(A/P - 1)r = (1/9)((300/81) - 1)Reduce the expression by cancelling the common factors.r=(1/9)(100/27−1)Combine 100/27 and −1 using a common denominator.r=(1/9)(100−1⋅27/27)Simplify the numerator.r=(1/9)(73/27)r = 0.30041152converting r decimal to a percentageR = 0.30041152 * 100 = 30.0412%/yearA. 3%
hope this helps
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Find the value of x that makes mln (8x - 22) (5x + 290°​
Anastasy [175]

Answer:

give me brainliest now plsssss

Step-by-step explanation:

(8x-22)=5x+29

We move all terms to the left:

(8x-22)-(5x+29)=0

We get rid of parentheses

8x-5x-22-29=0

We add all the numbers together, and all the variables

3x-51=0

We move all terms containing x to the left, all other terms to the right

3x=51

x=51/3

x=17

4 0
3 years ago
A function h(x) has zeroed at x=-6 and x=12 where does the function g(x) =h(3x) have zeroed?
saul85 [17]

Answer:.

Step-by-step explanation:.

7 0
3 years ago
What's the answer<br>what's the answer ​
Jet001 [13]

Answer:

a

Step-by-step explanation:

a

6 0
3 years ago
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6th grade math ! help me please :)
malfutka [58]
1. N + 2; n = 6: the answer is 8 because n=6 so we sub n with that... and we get 6+2 and that’s 8.

2.5f; where f=4: the answer is 20 because when a variable is directly next to a number it is multiplied by that number so we will replace f with 4 and our equation is now 5(4) or 5•4 and both are equivalent to 20.

3. 7b-2; where b=5: the answer is 33 because 7 multiplied by 5(b) minus 2= 7(5)-2 or 7•5-2= 33 because you will multiply 7 by 5 and get 33 then you will subtract by 2 and get 33.

Hope this helps!!!
7 0
3 years ago
How many extraneous solutions does the equation below have?
aev [14]

Answer:

A solution is said to be extraneous, if it is a zero of the equation, but it does not satisfy the equation,when substituted in the original equation,L.H.S≠R.H.S. 

The given equation consisting of  variable , m is

   \frac{2 m}{2 m+3} -\frac{2 m}{2 m-3}=1\\\\ 2 m[\frac{1}{2 m+3} -\frac{1}{2 m-3}]=1\\\\ 2 m\times \frac{[2 m-3 -2 m- 3]}{4m^2-9}=1\\\\ -6 \times 2 m=4 m^2 -9\\\\ 4 m^2 +1 2 m -9=0\\\\m=\frac{-12 \pm\sqrt{12^2-4 \times 4 \times (-9)}}{2\times 4}\\\\m=\frac{-12 \pm \sqrt {144+144}}{8}\\\\m=\frac{-12 \pm \sqrt {288}}{8}\\\\m=\frac{-12 \pm 12 \sqrt{2}}{8}\\\\m=\frac{3}{2}\times(-1 \pm \sqrt{2})

None of the two solution

m=\frac{3}{2}\times(-1 +\sqrt{2}) and , m=\frac{3}{2}\times(-1 -\sqrt{2}), is extraneous.

Here, L.H.S= R.H.S

Option A: 0→ extraneous

8 0
3 years ago
Read 2 more answers
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