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3 years ago

The left and right page numbers of an open book are two consecutive integers whose sum is 295. Find these page numbers.

Mathematics

1 answer:

artcher [175]3 years ago

3 0

Answer:

147, 148

Step-by-step explanation:

295/2=147 remainder 1 so, consecutive means back to back so 147 and 148. Add them up and you get 295.

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Can someone plz help plz show work

aliya0001 [1]

Answer:

Step-by-step explanation:

In the base we have the right triangle. Use the Pythagorean theorem for to calculate the hypotenuse:

$h^2=4^2+3^2\\\\h^2=16+9\\\\h^=25\to h=\sqrt{25}\\\\h=5\ ft$

The Lateral Area is the sum of the areas of three rectangles:

$4\ ft\ \times\ 2\ ft\to A_1=(4)(2)=8\ ft^2\\\\3\ ft\ \times\ 2\ ft\to A_2=(3)(2)=6\ ft^2\\\\5\ ft\ \times\ 2\ \ft\to A_3=(5)(2)=10\ ft^2$

The Lateral Area:

$LA=A_1+A_2+A_3\to LA=8+6+10=24\ ft^2$

8 0

3 years ago

You and your friend play a game. You answer 80% of the questions correctly and your friend answers 0.60 of the questions correct

bezimeni [28]

Answer:

Step-by-step explanation:

Assuming both players can answer the same question, the minimum number of questions is the smallest number that when multiplied by either 0.60 or 0.80 yields a whole number.

Let x be the number of questions, solving by trial and error:

$if\ x=2\\x*0.8=1.6\\x*0.6=1.2\\\\if\ x=3\\x*0.8=2.4\\x*0.6=1.8\\\\if\ x=4\\x*0.8=3.2\\x*0.6=2.4\\\\if\ x=5\\x*0.8=4\\x*0.6=3\\\\$

Therefore, the minimum number of questions in the game is 5.

5 0

3 years ago

From a point 50m from the base of the Skylon Tower in Niagara Falls, the angle of elevation to the top of

VladimirAG [237]

Answer:

The tower is about 235 m.

Step-by-step explanation:

Let x be the height of the tower

tan θ = opp / adj

tan 78 °= x / 50

x = 50 tan 78 °

x = 235

∴ The tower is about 235 m.

Hope this answer helps you :)

Have a great day

Mark brainliest

8 0

3 years ago

Evaluate. 1. for x=-3 and y=2

Sveta_85 [38]

<h3>Given:</h3>

X = - 3

Y = 2

2^ x^ y^

=2^ (-3)^ (2)^

= (-6)^(2)

3 0

2 years ago

If the local linear approximation of f(x) = 2cos x + e^2x at x = 2 is used to find the approximation for f(2.1), then the % erro

yKpoI14uk [10]

<u>Answer-</u>

The % error of this approximation is 1.64%

<u>Solution-</u>

Here,

$\Rightarrow f(x) = 2\cos x + e^{2x}$

$\Rightarrow f'(x) = -2\sin x + 2e^{2x}$

And,

$\Rightarrow f(2) = 2\cos 2 + e^{4}$

$\Rightarrow f'(2) = -2\sin 2 + 2e^{4}$

Taking (2, f(2)) as a point and slope as, f'(2), the function would be,

$\Rightarrow y-y_1=m(x-x_1)$

$\Rightarrow y-(2\cos 2 + e^{4})=(-2\sin 2 + 2e^{4})(x-2)$

$\Rightarrow y=(-2\sin 2 + 2e^{4})(x-2)+(2\cos 2 + e^{4})$

The value of f(2.1) will be

$\Rightarrow y=(-2\sin 2 + 2e^{4})(2.1-2)+(2\cos 2 + e^{4})$

$\Rightarrow y=(-2\sin 2 + 2e^{4})(0.1)+(2\cos 2 + e^{4})$

$\Rightarrow y=64.5946$

According to given function, f(2.1) will be,

$\Rightarrow f(2.1) = 2\cos 2.1 + e^{2(2.1)}$

$\Rightarrow f(2.1) = 65.6766$

$\therefore \%\ error=\dfrac{65.6766-64.5946}{65.6766}=0.0164=1.64\%$

5 0

3 years ago