Answer:
y = -1/2x + 6
Step-by-step explanation:
Find the slope
( 5 , 2) ( -3 , 6)
m =( y2 - y1 )/ ( x2 - x1)
x1 = 5
y1 = 2
x2 = -3
y2 = 6
m = ( 6 -2)/(-3 - 5)
m = 4/-8
m = - 1/2
Substitute m into the equation of a line
y = mx + c.
y = -1/2x + c
Substitute any of the two points given into the equation
Let's pick (2 ,5)
x = 2
y = 5
y = -1/2x + c
5 = -1/2(2) + c
5 = -1*2/2 + c
5 = -2/2 + c
5 = -1 + c
c = 5 + 1
c = 6
y = -1/2x + 6
The equation of the line is
y = -1/2x + 6
ANSWER: -3-2ji-8j^2
EXPLAINATION:
I dont know why that isn’t one of the answers but that’s what I got. You could try D.
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Answer:
B. 16 hrs
Step-by-step explanation:
Distance = rate × time
The best way to do this is to make a table with the info. We are concerned with the trip There and the Return trip. Set it up accordingly:
d = r × t
There
Return
The train made a trip from A to B and then back to A again, so the distances are both the same. We don't know what the distance is, but it doesn't matter. Just go with it for now. It'll be important later.
d = r × t
There d
Return d
We are also told the rates. There is 70 km/hr and return is 80 km/hr
d = r × t
There d = 70
Return d = 80
All that's left is the time column now. We don't know how long it took to get there or back, but if it took 2 hours longer to get There than on the Return, the Return trip took t and the There trip took t + 2:
d = r × t
There d = 70 × t+2
Return d = 80 × t
The distances, remember, are the same for both trips, so that means that by the transitive property of equality, their equations can be set equal to each other:
70(t + 2) = 80t
70t + 140 = 80t
140 = 10t
14 = t
That t represents the Return trip's time. Add 2 hours to it since the There trip's time is t+2. So 14 + 2 = 16.
B. 16 hours
Area : Multiply the two numbers
13*8=104 yd^2
Perimeter: Add the two numbers two times
Perimeter : 13+8+13+8=42 yd
Answer:
Area is 104yd^2
Perimeter is 42yd
Answer:
y=29
Step-by-step explanation:
mark me please
and rate
