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Elena-2011 [213]
4 years ago
9

6(8-x)(x+4)=0 what’s the solution set?

Mathematics
1 answer:
Travka [436]4 years ago
6 0

Answer:

x_{1} = -4\\\\x_{2} = 8

Step-by-step explanation:

6(8-x)(x+4)=0

(48 -6x )(x+4) = 0

48x +192 -6x^2 -24x = 0

6x^2 -24x -192=0

using quadratic formula:

x =\frac{-b+-\sqrt{b^{2}-4*a*c}}{2*a}

a= 6   b= -24  c= -192

we have:

x_{1} = -4\\\\x_{2} = 8

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