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Savatey [412]
3 years ago
14

GUYS I NEEDA SUBMIT THIS ASAP PLSSSSSSSS HELP OMG :''''''((

Mathematics
1 answer:
Ghella [55]3 years ago
7 0

Given coordinates of the triangle RST are R(2,1), S(2,-2) and T(-1,-1).


Center of center of dilation is (2,-2).


Because center of dilation is (2,-2) so the coordinates of dilated image S(2,-2) would stay same.


Now, we need to apply rule for dilation with the scale factor 5/3.


<em>Each of R(2,1), and T(-1,-1) would be and R' and T' would be in ratio 5/3.</em>


<em>We will extend RS to 5 units and TS also 5 units.</em>


The new resulting image would be dilated triangle by a scale factor 5/3.


New coordinates would be

R'(2,3), S'(2,-2) and T'(-3,-2)


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3 years ago
Please answer ASAP
labwork [276]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

A 12 cm cone with a dome on top of it that has an 8 cm diameter

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cone volume)

V = \dfrac{ \pi *r^2*h}{3}

V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}

V = 3.14*16*4

\boxed{V = 200.96\:cm^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{4^3}{3}

V = 2*3.14 * \dfrac{64}{3}

V = \dfrac{401.92}{3}

\boxed{ V_{hemisphere} \approx 133.97\:cm^3}

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

\boxed{\boxed{\boxed{Volume\:of\:the\:figure = 334.93\:cm^3}}}\end{array}}\qquad\quad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)

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661 ^{5}  \\  = 661 \times 661 \times 661 \times 661 \times 661 \\  = \boxed{ 126,184,873,719,301}

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2 years ago
Read 2 more answers
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