He area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
<span>(x - x^2)^2 * sqrt(3)/4. </span>
<span>Integrating from x = 0 to x = 1, we have </span>
<span>[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4 </span>
<span>= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144. </span>
<span>Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
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Step-by-step explanation:
-10 is the correct answer of your Question
Answer: y = x/2 + 3
Step-by-step explanation:
The equation of a straight line can be represented in the slope-intercept form, y = mx + c
Where c = intercept
Slope, m = change in value of y on the vertical axis / change in value of x on the horizontal axis
change in the value of y = y2 - y1
Change in value of x = x2 -x1
y2 = final value of y
y 1 = initial value of y
x2 = final value of x
x1 = initial value of x
Looking at the graph,
y2 = 6
y1 = 4
x2 = 6
x1 = 2
Slope,m = (6 - 4)/(6 - 2) = 2/4 = 1/2
To determine the intercept, we would substitute x = 2, y = 4 and m= 1/2 into y = mx + c. It becomes
4 = 1/2 × 2 + c
4 = 1 + c
c = 4 - 1
c = 3
The equation becomes
y = x/2 + 3
Answer:
it is 4y for answer
Step-by-step explanation:
6 and 4 would switch
Answer:
A. ∠AOD = 170°
Step-by-step explanation:
103° + 55° + 12° = 170°