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aleksandr82 [10.1K]
4 years ago
15

The quotient of n and -4 is 8. What is the value of n?

Mathematics
1 answer:
Phoenix [80]4 years ago
8 0

Answer:

n = -32

Step-by-step explanation:

quotient means divide

n/-4 = 8

Multiply each side by -4

n/-4 *-4 = 8*-4

n = -32

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Arun scores 36 marks in English 44 marks in Hindi and 75 marks in maths and X in Science if average score is 50 find the value o
Gnoma [55]

Answer:

x = 45

Step-by-step explanation:

The average is calculated as

average = \frac{score}{count}

here the average = 50 , thus

\frac{36+44+75+x}{4} = 50

Multiply both sides by 4

36 + 44 + 75 + x = 200

155 + x = 200 ( subtract 155 from both sides )

x = 45

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Perimeter of 24.5 and 31.7
Bezzdna [24]

If they are the sides of rectangle, then it's perimeter would be:

2(l+b) = 2(24.5+31.7) = 2(56.2) = 112.4

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3 years ago
I need help on the table. Image inserted! Please help me
wel

Answer: (6) $172.50    (7) $74.80   (8) $106.65   (9) $141.20

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<u>Step-by-step explanation:</u>

Use the following formula <em>(+ for markup and - for markdown/discount)</em>

Base Price ± (Base Price × markup/markdown) = Adjusted Price

6. <em>Markup so add (+)</em>

150 + (150 × 0.15) = x

150 +      22.5       = x

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7. <em>Markdown so subtract (-)</em>

85 - (85 × 0.12) = x

85 -      10.2      = x

             74.80  = x

8. <em>Discount so subtract (-)</em>

135 - (135 × 0.21) = x

135 -       28.35    = x

              106.65  = x

9. <em>Markup so add (+)</em>

x + (x × 0.25) = 176.50

x  +    0.25x   = 176.50

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10. <em>Markdown so subtract (-)</em>

x - (x × 0.15) = 101.15

x -    0.15x    = 101.15

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11. <em>The adjusted price is more than the base price so add (+)</em>

278 + (278 × x) = 312.75

278 +      278x  = 312.75

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12. <em>The adjusted price is less than the base price so subtract (-)</em>

157 - (157 × x) = 133.45

157 -    157x    = 133.45

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                x     = 0.15

                x     = 15% markdown

4 0
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Answer:

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Put $+0Ry in comments for points
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Answer:$+0Ry what is the meaning?

Step-by-step explanation:

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