The answer is; glycolysis
This process converts glucose molecule to pyruvate. It is an oxygen-independent pathway, unlike the Krebs cycle. Glycolysis occurs in the cell cytoplasm while the Krebs cycle (aerobic pathway) occurs in the mitochondria. In the presence of oxygen, the product of glycolysis, i.e pyruvate, is fed to the Krebs cycle. If oxygen is unavailable the pyruvate is converted to lactate.
Answer:
The fist option!
Explanation:
The energy investment phase of glycolysis involves the investment of two ATP molecules and results in the formation of two molecules of glyceraldehyde phosphate. Two molecules of NADH + H+ are produced. This is an example of a coupled reaction.
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Answer:
Lactose contains a lot of processed sugars found in food sources such as milk, yogurt, and cheese.
Answer: a) true
Explanation:
The goal of mitosis is to produce daughter cells that are genetically identical to the mother cell, without a single extra or missing chromosome. Meiosis, on the other hand, is only used for one purpose in the human body: the production of gametes or sex cells, i.e. sperm and eggs. The question is oriented to mitosis, <u>in which prior to this cell division, the cell duplicates its DNA</u> so that each daughter cell then inherits the genetic material. That is, the cell originally possesses 23 chromosomes, they duplicate to a total of 46 so that then each daughter cell receives 23.
The metaphase is the second phase of mitosis and meiosis that occurs after prophase where the envelope is lost and microtubules of the achromatic spindle (also called meiotic or mitotic) appear.
During metaphase, the chromosomes align themselves in the middle of the cell and this balanced midline spindle alignment is due to the equal and opposing forces generated by the kinetochore brothers.
Then during metaphase, the chromosomes will line up in the center of the cell to be separated and go each to a different daughter cell. But the moment they're found there, each orientation of chromosomes produces gametes with the same genetic information from each parent. <u>Because because there have been no changes or mutations in the chromosomes, they have duplicated and have the same genetic information.</u>
Answer:
B. As the distance between loci increases, some multiple crossovers go undetected such that the relationship between recombination frequency and map distance ceases to be linear.
Explanation:
When calculating recombination frequencies, and hence, map distances, we might notice that these distances are not completely additive. They might vary. <em>For example, let us say that we have three genes, A, B, and C, in that order. </em>We calculated that the <em>distance between A and B equals 5.9</em> MU and that <em>B and C are 19.5 MU apart.</em> According to this, we might say that the <em>total distance between A and C is 25.4 MU (5.9 + 19.5). </em>However, after a<em> two-point calculation between A and C, the value equals 23.7 MU. </em>
The recombination frequency between these two genes located in the extremes and far apart underestimate the actual genetic distances between them because there might occur other crossing-overs that were not detected. This is <em>when calculating the distance between A and C, we probably will not detect the occurrence of a double recombinant between them, and hence, we might sub-estimate the real distance.</em>
The relationship between the actual map distance (number of crossing overs) and the recombination frequency between two loci, is not lineal. The farther apart are the two genes, the worse is the distance estimation.
