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3 years ago

HELP HELP HELP HELP HELP PELADE PLEASE PLEASE IM DESPERATE SNSMXMDMAK

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

6 0

Answer:

see below

Step-by-step explanation:

The points at the corners of the given figure are ...

(0, 0), (0, 4), (3, 4), (3, 0)

When the figure is scaled by a factor of 1/3, each of the coordinates is multiplied by 1/3:

(0, 0), (0, 4/3), (1, 4/3), (1, 0) . . . . . points scaled by 1/3

When the figure is scaled by a factor of 3/2, each of the coordinates is multiplied by 3/2:

(0, 0), (0, 6), (9/2, 6), (9/2, 0) . . . . . . points scaled by 3/2

The points that are on your list are shown in bold above.

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Ginny is studying a population of frogs. She determines that the population is decreasing at an average rate of 3% per year. Whe

Rama09 [41]

You can see how this works by thinking through what's going on.

In the first year the population declines by 3%. So the population at the end of the first year is the starting population (1200) minus the decline: 1200 minus 3% of 1200. 3% of 1200 is the same as .03 * 1200. So the population at the end of the first year is 1200 - .03 * 1200. That can be written as 1200 * (1 - .03), or 1200 * 0.97

What about the second year? The population starts at 1200 * 0.97. It declines by 3% again. But 3% of what??? The decline is based on the population at the beginning of the year, NOT based no the original population. So the decline in the second year is 0.03 * (1200 * 0.97). And just as in the first year, the population at the end of the second year is the population at the beginning of the second year minus the decline in the second year. So that's 1200 * 0.97 - 0.03 * (1200 * 0.97), which is equal to 1200 * 0.97 (1 - 0.03) = 1200 * 0.97 * 0.97 = 1200 * 0.972.

So there's a pattern. If you worked out the third year, you'd see that the population ends up as 1200 * 0.973, and it would keep going like that.

So the population after x years is 1200 * 0.97x

5 0

3 years ago

Nina has some nickels and 9 pennies in her pocket. Her friend, Maurice has twice as many nickels as Nina. Together these coins a

algol13

So Maurice would have 2N nickels

Total number of coins is N + 2N + 9 = 3N + 9

Each nickel is 5 pennies

3N of nickels = 15N pennies

-----------

Their worth is 84 cents

15N + 9 = 84

15N = 75

N = 75/15 = 5

N = 5

This means Nina has 5 nickels.

4 0

3 years ago

What is the measure of angle a. round your answer to the nearest hundredth

joja [24]

Answer:use a right triangle calc. On the web it does it for you and shows you how it got the answer.

Step-by-step explanation:

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2 years ago

Yo! Solving linear equations with integers! These are just some practice exercises I need help with! So they should probably be

drek231 [11]

Answer:

Step-by-step explanation:

<h3>Solving linear equation with one variable:</h3>

1) -4 + 3x = 4x - 8

Add 4 to both sides

-4 + 3x + 4 = 4x - 8 + 4

3x = 4x - 4

Subtract 4x from both sides,

3x - 4x = -4x + 4x - 4

-x = -4

$\sf \boxed{\bf x = 4}$

2) -5x - 8 = 2

Add 8 to both sides

-5x - 8 + 8 = 2 + 8

-5x = 10

Divide both sides by (-5)

$\sf \dfrac{-5}{-5}x =\dfrac{10}{-5}$

$\sf \boxed{\bf x = -2}$

3) 12r - 14 = 5(2-r)

12r - 14 = 5*2 - 5*r

12r - 14 = 10 - 5r

Add 14 to both sides

12r - 14 + 14 = 10 - 5r + 14

12r = 24 - 5r

Add 5r to both sides

12r + 5r = 24

17r = 24

Divide both sides by 17

r = 24/17

4) 3x - 8 = -(17 + 2x)

3x - 8 = -17 - 2x

Add 8 to both sides

3x - 8 + 8 = -17 - 2x + 8

3x = -9 - 2x

Add 2x to both sides

3x + 2x = -9

5x = -9

Divide both sides by 5

$\sf \dfrac{5}{5}x=\dfrac{-9}{5}\\\\\boxed{x = \dfrac{-9}{5}}$

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2 years ago

Read 2 more answers

3•r^6 is equivalent to:? <br> Need help

Korvikt [17]

I think the answer is r< 18

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3 years ago