Question

How do i find the missing sides?

Answer 1

4. You're right that the leg labeled $x$ occurs in a 1-to-2 ratio with the hypotenuse, but more to the point, it also occurs with the leg of length 10 in a 1-to-$\sqrt3$ ratio. In other words,

$10=x\sqrt3\implies x=\dfrac{10}{\sqrt3}$

and so

$2x=\dfrac{20}{\sqrt3}$


5. In this kind of triangle, the legs form a 1-to-$\sqrt2$ ratio with the hypotenuse, so it follows that $x=2.1$.

6. You have $x$ and $x\sqrt3$ mismatched. The larger leg in this kind of triangle has the $\sqrt3$ scaling factor. So in fact, $x=25$, which makes the larger leg $x\sqrt3=25\sqrt3$, and the hypotenuse would be $2x=50$.