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Mashcka [7]
3 years ago
13

The center of an ellipse is located at (0, 0). One focus is located at (12, 0), and one directrix is at x = 14 1/12.

Mathematics
2 answers:
muminat3 years ago
6 0
The standard equation for an ellipse is
\frac{(x-h)^{2}}{a^{2}} + \frac{(y-k)^{2}}{b^{2}} =1
where
(h,k) = coordinates of the center
a, b = semi-major and semi-minor axes

Refer to the figure shown below.
The center of the ellipse is at (0,0). 
Therefore, h=0, k=0.

One focus is at (12, 0)
Therefore
c = 12

One directrix is at  14 1/12 = 169/12.
Because the directrix is located at x = a²/c, therefore
a²/12 = 169/12
a² = 169/144
a = 13

Because c² = a² - b², obtain
b² = a² - c²
     = 169 - 144 = 25
b = 5

Answer:
The equation for the ellipse is
\frac{x^{2}}{169} + \frac{y^{2}}{25} =1

malfutka [58]3 years ago
5 0

Answer:

Its A

Step-by-step explanation:

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

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Step-by-step explanation:

7*2x=14x

7*3=21

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Find the value of this expression if x=-1 and y=-5 x^2y/4
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\large\boxed{-\dfrac{5}{4}=-1\dfrac{1}{4}}

Step-by-step explanation:

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4 0
2 years ago
Please help math i will give good rating and 5 stars if answer question
Talja [164]

Hey!

Let's walk through this together.

Possible Answers: {5, 7, 9, 11, 13}

Let's start with 5.

5-4<8

1<8

So, 5 is CORRECT.

Next, 7.

7-4<8

3<8

So, 7 is CORRECT.

Next, 9.

9-4<8

5<8

So, 9 is CORRECT.

Next, 11.

11-4<8

7<8

So, 11 is CORRECT.

Last, 13.

13-4<8

11<8

So, 13 is INCORRECT.

Your answers are: {5,7,9,11}

So D.

Hope this helps!

<h2><em>~~~PicklePoppers~~~</em></h2>
4 0
2 years ago
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