Answer:
H0 : mu1 = mu2
Ha : mu1 ≠ mu2
Which means
Null hypothesis H0; the true mean price when buying from a friend mu1 and the true mean price when buying from a stranger mu2 is the same/equal
Alternative hypothesis Ha; the true mean price when buying from a friend mu1 and the true mean price when buying from a stranger mu2 is different (not equal)
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean(i.e it tries to prove that the old theory is true). While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.
Therefore, for the case above;
H0 : mu1 = mu2
Ha : mu1 ≠ mu2
Which means
Null hypothesis H0; the true mean price when buying from a friend mu1 and the true mean price when buying from a stranger mu2 is the same/equal
Alternative hypothesis Ha; the true mean price when buying from a friend mu1 and the true mean price when buying from a stranger mu2 is different (not equal)
Answer:
The answer is 200
Step-by-step explanation:
Answer:
26 cm
Step-by-step explanation:
I am trying to post the full solution of the question.. But it displays a message:
RUDE!! WE DON'T USE SUCH WORDS
PLEASE CHANGE IT!!
I was just posting the solution and no wrong word.
Part 1:
The probability of a binary distribution x ~ bin(n, p) is given by
Part 2:
Part 3:
![P(X\geq4)=P(4)+P(5)+ . . . +P(25) \\ \\ =1-P(x\ \textless \ 4)=1-[P(0)+P(1)+P(2)+P(3)] \\ \\ =1-0.9659=\bold{0.0341}](https://tex.z-dn.net/?f=P%28X%5Cgeq4%29%3DP%284%29%2BP%285%29%2B%20.%20.%20.%20%2BP%2825%29%20%5C%5C%20%20%5C%5C%20%3D1-P%28x%5C%20%5Ctextless%20%5C%204%29%3D1-%5BP%280%29%2BP%281%29%2BP%282%29%2BP%283%29%5D%20%5C%5C%20%20%5C%5C%20%3D1-0.9659%3D%5Cbold%7B0.0341%7D)
Answer:
Step-by-step explanation:
Let's simply rearrange bringing y to the RHS, -7 to the LHS and reading right to left:
