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ratelena [41]
4 years ago
8

How would you solve this problem 999 + 587 = 1000 + what = what ? How would this problem be solved

Mathematics
2 answers:
rewona [7]4 years ago
7 0

Answer:

999+587 = 1000+586

both of them equals 1586

HOPE IT HELPS

bija089 [108]4 years ago
3 0

Answer:

2,586

Step-by-step explanation:

Add 1000+1000

2000

Since its 999 not 1000 subtract 1

1999

Now add 1 and subtract 1 from 587

Then add 2000 with 586

2,586

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3 years ago
A simple random sample of 25,000 individuals are surveyed in order to determine the prevalence of individuals that contracted th
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Answer:

The prevalence of flu for the past year, as indicated from the survey participants, was of 17%.

Step-by-step explanation:

Given the survey, the prevalence of the flu, as a percentage, is given by:

Number of individuals diagnosed with flu, multiplied by 100, and divided by the size of the sample.

In this question, we have that:

Sample of 25,000, and 4,250 of those had been diagnosed with the flu at some point in the past year. So, the prevalence of the flu is given by:

\frac{4250*100}{25000} = 17

The prevalence of flu for the past year, as indicated from the survey participants, was of 17%.

4 0
3 years ago
What is the slope of this line?​
Fed [463]

Answer:

(-5,4)

Step-by-step explanation:

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Hope This Helps

7 0
3 years ago
Read 2 more answers
There were 324 adults surveyed. Among the participants, the mean number of hours of sleep each night was 7. 5 and the standard d
NeTakaya

The margin of error for 324 adults surveyed with 1.6 standard deviations is 0.1742.

<h3>What is the margin of error?</h3>

The margin of error can be defined as the amount of random sampling error in the results of a survey. It is given by the formula,

\text{MOE}_{\gamma}=z_{\gamma} \times \sqrt{\frac{\sigma^{2}}{n}}

\text{MOE} = margin of error

\gamma = confidence level

z_{\gamma} = quantile

σ = standard deviation

n = sample size

As it is given that the sample size of the survey is 324, while the standard deviation of the survey is 1.6.

We know that the value of the z for 95% confidence interval is 1.96. Therefore, using the formula of the standard of error we can write it as,

\text{MOE}_{\gamma}=z_{\gamma} \times \sqrt{\dfrac{\sigma^{2}}{n}}\\\\\text{MOE}_{\gamma}=1.96 \times \sqrt{\dfrac{1.6^{2}}{324}}\\\\\text{MOE}_{\gamma}=0.1742

Hence, the margin of error for 324 adults surveyed with 1.6 standard deviations is 0.1742.

Learn more about Margin of Error:

brainly.com/question/6979326

5 0
3 years ago
CAN SOMEONE PLEASE SOLVE THIS????????
defon
Which one question? there is multiple in there.
3 0
3 years ago
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