Can I get help with part B & C
1 answer:
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Answer:
C
Step-by-step explanation:
From the given coordinates
A(6, 0), B(0, 0) then AB = 6 - 0 = 6
B(0, 0), C(0, 8) then BC = 8 - 0 = 8
To calculate AC use Pythagoras' theorem on the right triangle formed
AC² = AB² + BC² = 6² + 8² = 36 + 64 = 100
Take the square root of both sides, hence
AC = = 10
Perimeter = AB + BC + AC = 6 + 8 + 10 = 24 → C
True
It won’t be a Prefect Triangle but it still is one
(sorry my drawing is bad)
It won’t be a Prefect Triangle but it still is one
(sorry my drawing is bad)