Answer:
The theory of punctuated equilibrium states that evolutionary change is characterised by short periods of rapid evolution followed by longer periods of stasis in which no change occurs. ... To meet this challenge, evolutionary biologists attempt to describe how and why evolutionary changes accumulate over time
Explanation:
Answer:
Mutations in introns create alternative splicing site which in turn make mRNA with reduced or no translation.
Explanation:
Introns regulate the splicing of heterogenous RNA during post transcriptional modifications as well as affect the stability of mature mRNA. The stable mRNA is more likely to be translated into proteins. So, introns also regulate the translation of mRNA.
In human beta thalassemia, mutations in intron create alternative splicing sites which in turn affect the formation of beta globin chain of hemoglobin. Lack of beta globin chain reduces the amount of functional hemoglobin and causes anemia.
Ewaste is a problem because it contains many hazardous chemicals like mercury, lead and cadmium which could seep in to the soil and eventually to the groundwater. This would lead to contamination of the drinking water. The most important thing to remember would be to separate this type of waste with the others. It would be better if you sell it or give it for reuse. Also, you can send it to a recycler that knows what to do with these wastes.
Correct answer is True
Please mark as brainiest
a) Evolutionary fitness can be characterized as a person's commitment to the cutting edge's quality pool,which is chiefly founded on the aggregate or the genotype of the individual.This principally identifies with the conceptive achievement of an organic entity.
It is fundamentally determined by the offspring that can endure and pass on the characteristics/traits.
b) Graph is already uploaded in the below attached document.
c) The population 3 will have the most elevated frequency of heterozygotes,45% of the complete population.
d) Since population 2 is as of now having a low number of heterozygotes, the occasion would totally eliminate them from the population or decreases their number
Explanation:
Frequency of animals in population 1 having both alleles 1 and 3
frequency of allele 1 =0.60
frequency of allele 3= 0.25
Frequency of both allele 1 and 3 would be allele 1 + allele 3 frequency x 100
= 0.60+0.25 X 100= 85%