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mihalych1998 [28]
3 years ago
6

B) A factor of 30 is chosen at random.

Mathematics
1 answer:
BigorU [14]3 years ago
7 0

Answer:

0.375

Step-by-step explanation:

Listing the factors of 30

1, 2, 3, 5, 6, 10, 15, 30 ← that is 8 factors

There are 3,  2- digit factors, that is 10, 15, 30

Thus the probability of choosing a 2- digit number factor is

\frac{3}{8} = 0.375

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A standard number die is tossed. Find P(4 or even).
zmey [24]

Answer:

50%

Step-by-step explanation:

4 0
3 years ago
Find center,foci, and vertices of ellipse (x+3)^2/21+(y-5)^2/25=1
sasho [114]
I don't know if we can find the foci of this ellipse, but we can find the centre and the vertices. First of all, let us state the standard equation of an ellipse. 

(If there is a way to solve for the foci of this ellipse, please let me know! I am learning this stuff currently.) 

\frac{(x-x_{1})^2}{a^2}+ \frac{(y-y_{1})^2}{b^2}=1

Where (x_{1},y_{1}) is the centre of the ellipse. Just by looking at your equation right away, we can tell that the centre of the ellipse is: 

(-3,5)

Now to find the vertices, we must first remember that the vertices of an ellipse are on the major axis. 

The major axis in this case is that of the y-axis. In other words, 

b^2>a^2 

So we know that b=5 from your equation given. The vertices are 5 away from the centre, so we find that the vertices of your ellipse are: 

(-3,10)
 & (-3,0)

I really hope this helped you! (Partially because I spent a lot of time on this lol) 

Sincerely,

~Cam943, Junior Moderator
6 0
4 years ago
Graph the system of inequalities presented here on your own paper, then use your graph to answer the following questions:
MrMuchimi
No, it is not in the solution area for the system.

The point only works in one of the inequalities. 

It doesn't work in the inequality: y > -1/2x+ 3

We can put it in to test it:

-7 > (-1/2)3 + 3
-7 > -1.5 + 3
-7 > 1.5  This is a false statement, therefore it is not part of the solution.
5 0
4 years ago
HELP ASAP! Please give a detailed explanation!
mash [69]

Answer:

If the first die is a 5, the second must be 5 or more in order to have a sum of at least ten.

Assuming it is a six sided die, the two values that would make this true are 5 and 6.

2 values/6 possible would be a probability of 2/6, which simplifies to 1/3

Final answer: 1/3

Step-by-step explanation:

6 0
3 years ago
A student takes an 18-question, multiple-choice exam with five choices for each question and guesses on each question. Assume th
Kobotan [32]

Answer:

Probability of getting at least 9 out of 18 correctly is 0.0043

Step-by-step explanation:

We have

n = 18

p = 1/5 for correct answer

q = 4/5 for wrong answer

P( 9 \leq X \leq 18) = 1 - P(0 \leq X\leq 8)

                       = 1 -  0.9957

                         =0.0043

7 0
3 years ago
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