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mihalych1998 [28]
3 years ago
6

B) A factor of 30 is chosen at random.

Mathematics
1 answer:
BigorU [14]3 years ago
7 0

Answer:

0.375

Step-by-step explanation:

Listing the factors of 30

1, 2, 3, 5, 6, 10, 15, 30 ← that is 8 factors

There are 3,  2- digit factors, that is 10, 15, 30

Thus the probability of choosing a 2- digit number factor is

\frac{3}{8} = 0.375

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According to data from the American Medical Association, 10% of us are left handed. If three people are randomly selected, find
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Answer:

For each person, there are only two possible outcomes. Either they are left handed, or they are not. The probability of a person being left-handed is independent from other people. So we use the binomial probability distribution to solve this question.

0.1% probability that they are all left-handed.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are left handed, or they are not. The probability of a person being left-handed is independent from other people. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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And p is the probability of X happening.

10% of us are left handed.

This means that p = 0.1

If three people are randomly selected, find the probability that they are all left-handed.

This is P(X = 3) when n = 3. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.1)^{3}.(0.9)^{0} = 0.001

0.1% probability that they are all left-handed.

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