Question

What is the product?

Answer 1

For this case we have:

By definition, the distributive property states that:

$(a + b) (c + d) = ac + ad + bc + bd$

In addition, we know that: $ax * bx = (ab) x ^ 2$, that is, the exponents are added together.

If we have:$(4y - 3)\ and\ (2y ^ 2 + 3y - 5)$, your product is given by:

$(4y - 3) (2y ^ 2 + 3y - 5) = (4 * 2) y^{1 + 2} + (4 * 3) y^{1 + 1} - (4 * 5) y^{1 +0} - (3 * 2) y ^ {0 + 2} - (3 * 3) y ^ {0 + 1} - (3 * (-5))$

$(4y - 3) (2y ^ 2 + 3y - 5) = 8y ^ 3 + 12y ^ 2-20y ^ 1-6y ^ 2-9y ^ 1 - (- 15)$

$(4y - 3) (2y ^ 2 + 3y - 5) = 8y ^ 3 + (12-6) y^ 2 + (- 20-9)y - (-15)$

Taking into account that equal signs are added and the same sign is placed, and that $- * - = +$we have:

$(4y - 3) (2y ^ 2 + 3y - 5) = 8y ^ 3 + 6y ^ 2-29y + 15$

So,$(4y - 3) (2y ^ 2 + 3y - 5) = 8y ^ 3 + 6y ^ 2-29y + 15$

Answer:

Option D

Answer 2

The anwser is 8y^3+6y^2-29y+15 so D