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Nat2105 [25]
3 years ago
14

Chad jogs 4 2/5 miles in 1/2 hour. What is his average speed in miles per hour?

Mathematics
1 answer:
pentagon [3]3 years ago
7 0
Chad jogs 8 4/5 miles per hour.
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What is the solution of<br><br>log6x + log6(x + 5) = 2?
exis [7]

Answer:

Doesn't have solution.

Step-by-step explanation:

x ≠ 0; x > 0 (I)

x - 5 > 0

x > 5 (II)

log_6 x + log_6 (x + 5) = 2 \\\ log_6 [x(x + 5)] = 2 \\\ x^2 + 5x = 36 \\\ x^2 + 5x - 36 = 0 \\\ \Delta = 5^2 - 4.1.(- 36) \\\ \Delta = 169 \\\ \sqrt{\Delta} = \pm 13 \\\ x' = \frac{- 5 + 13}{2} \\\\ x' = 4 \\\ x" = \frac{- 5 - 13}{2} \\\\ x" = - 9

Then, this expression doesn't have solution.

I Hope I've helped you.

4 0
3 years ago
Read 2 more answers
Plz help I can’t figure this out
Julli [10]

Answer:

57

Step-by-step explanation:

9+6 (2^2 +4)\\9+6 (4 +4)\\9+6 *8\\9+48\\57

Your answer is 57.

Hope this helps! Brainliest would be much appreciated! Have a great day! :)

6 0
2 years ago
Read 2 more answers
Is 4/5 greater then 0.75
GalinKa [24]
Yes 4/5 is greater than 0.75 because if you put 0.75 as a fraction that would be 75/100 then you do the same denominator and 5 can go into 100 20 times and so you do that to the numerator and you get 80/100 and 75/100 so 4/5 id grater than 0.75.
4 0
3 years ago
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a cirlcular patio has a diameter of 26ft. inside it is a round flower garden with a diameter of 6ft. to edge the patio and the g
Luden [163]

Answer: C just took the test

Step-by-step explanation:

5 0
3 years ago
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A business has two loans totaling $50,000. One loan has a rate of 8% and the other has a rate of 12%. This year, the business ex
Debora [2.8K]

Answer:

the 8% loan has a principal of $37500

the 12% loan has a principal of $12500

Step-by-step explanation:

Let's start by writing the general  equation for the interest hwre I is the interest, P is the principal (in our case would be loan amounts), "r" is the interest rate in decimal form (in our case one would be 0.12, and the other one 0.08), and t is the time in years (in our case 1 year).

I=P*r*t

Then we write the interest equation coming from each loan at the end of this year (we call I1 the interest coming from the 12% loan and I2 the interest coming from the 8% one). Since we don't know the loan amounts (in fact those are what we need to find) we will name one "x" and the other "y":

I=P*r*t\\I1=x * 0.12*1\\I2=y*0.08*1

Next, we add these last two equations term by term, and replace the addition of both interests by $4500 as given in the information:

I1=x * 0.12*1\\I2=y*0.08*1\\I1+I2 = 0.12x+0.08y\\4500=0.12x+0.08y

This is our first equation in the variables x and y which are our unknowns.

Now we generate the second equation on x and y by writing in agebraic terms the other piece of information we have: "the total of the two loans is $50000. That is the addition of the principals x and y should equal $50000:

x+y=50000

We solve for y in this last equation and replace its form in terms of x in the equation of the interest, and solve for the unknown x:

y=50000-x\\4500 = 0.12x +0.08 y\\4500=0.12x+0.08(50000-x)\\4500=0.12x+4000-0.08x\\4500=0.12x-0.08x+4000\\4500=0.04x+4000\\4500-4000=0.04x\\500=0.04x\\x=\frac{500}{0.04} =12500

Therefore the amount of the loan at 12% is $12500

Now to find the amount of the second loan "y" we use the equation for the totals of the loans:

x+y=50000\\12500+y=50000\\y=50000-12500=37500

Therefore, the loan at 8% is $37500

5 0
3 years ago
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