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3 years ago

Can y’all help me out?

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

6 0

20/x+11=10/x+3
20(x+3)=10(x+11)
20x + 60 = 10x + 110
10x = 50
x = 5

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7x + 9 = 58? solve for x

mars1129 [50]

The answer for the equation is x=7

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3 years ago

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Which data set has a median of 9?

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B. I believe because it is in the middle.

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What is the equation of a line that passes through the point (5, −4) and is parallel to the line whose equation is 2x + 5y = 10?

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36=4/9d what does d equal

soldier1979 [14.2K]

Answer:

d = 81

Step-by-step explanation:

Solve for d:

36 = (4 d)/9

Hint: | Reverse the equality in 36 = (4 d)/9 in order to isolate d to the left hand side.

36 = (4 d)/9 is equivalent to (4 d)/9 = 36:

(4 d)/9 = 36

Hint: | Multiply both sides by a constant to simplify the equation.

Multiply both sides of (4 d)/9 = 36 by 9/4:

(9×4 d)/(4×9) = 9/4×36

Hint: | Express 9/4×4/9 as a single fraction.

9/4×4/9 = (9×4)/(4×9):

(9×4)/(4×9) d = 9/4×36

Hint: | Express 9/4×36 as a single fraction.

9/4×36 = (9×36)/4:

(9×4 d)/(4×9) = (9×36)/4

Hint: | Cancel common terms in the numerator and denominator of (9×4 d)/(4×9).

(9×4 d)/(4×9) = (4×9)/(4×9)×d = d:

d = (9×36)/4

Hint: | In (9×36)/4, divide 36 in the numerator by 4 in the denominator.

36/4 = (4×9)/4 = 9:

d = 9×9

Hint: | Multiply 9 and 9 together.

9×9 = 81:

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3 years ago

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The number of corn stalks in each row of field can be modeled by arithmetic sequence.The 5th row in this field has 36 corn stalk

Mice21 [21]

Answer:

a_{n}=20+4(n-1)

Step-by-step explanation:

It is given that the number of corn stalks in rows of the field can be modeled by an arithmetic sequence.

The 5th row has 36 corn stalks. This means 5th term of the sequence is 36. i.e.

$a_{5}=36$

The 12th row has 64 stalks. So,

$a_{12}=64$

In order to write the explicit rule we need to find the first term(a1) and common difference(d) of the sequence.

The explicit rule for the arithmetic sequence is of the form:

$a_{n}=a_{1}+(n-1)d$

Writing the 5th and 12th term in this way, we get:

$a_{5}=a_{1}+4d$

$a_{1}+4d=36$ Equation 1

Similarly for 12th term, we can write:

$a_{1}+11d=64$ Equation 2

Subtracting Equation 1 from Equation 2, we get:

7d = 28

d = 4

Using the value of d in Equation 1, we get:

$a_{1}+4(4)=36\\\\ a_{1}=20$

Thus, for the given sequence first term is 20 and common difference is 4. Using these values in the general explicit rule, we get:

$a_{n}=20+4(n-1)$

7 0

3 years ago