3 years ago

I need help with this question

Mathematics

1 answer:

creativ13 [48]3 years ago

5 0

The 2nd option from the top

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Let y′′′−9y′′+20y′=0. find all values of r such that y=erx satisfies the differential equation. if there is more than one correc

DerKrebs [107]

we are given

differential equation as

$y'''-9y''+20y'=0$

we are given

$y=e^{rx}$

Firstly, we will find y' , y'' and y'''

those are first , second and third derivative

First derivative is

$y'=re^{rx}$

Second derivative is

$y''=r*re^{rx}$

$y''=r^2e^{rx}$

Third derivative is

$y'''=r^2*re^{rx}$

$y'''=r^3e^{rx}$

now, we can plug these values into differential equation

and we get

$r^3 e^{rx}-9r^2 e^{rx}+20re^{rx}=0$

now, we can factor out common terms

$e^{rx}(r^3 -9r^2 +20r)=0$

we can move that term on right side

$(r^3 -9r^2 +20r)=0$

now, we can factor out

$r(r^2 -9r +20)=0$

$r(r-5)(r-4)=0$

now, we can set them equal

$r=0$

$r-5=0$

$r=5$

$r-4=0$

$r=4$

so, we will get

$r=0,4,5$ ...............Answer

4 0

3 years ago

What point would be reflected across the y-axis to ( − 3, − 9) ?

Aloiza [94]

Answer:

(-3, 9)

Step-by-step explanation:

If a point was reflected across the y-axis, then the y-coordinate would change signs (from negative to positive or from positive to negative). Using this, we could find the original point by changing the sign of the y-coordinate. As you may already see, this is really just reflecting the point across the y-axis again. By doing this, you get the point (-3, 9).

The point would be (-3, 9).

I hope this helps. :)

5 0

2 years ago

Hey Guys, Thank you for all your help and support. I was wondering if you could help me one last time, I'm really confused. Than

SCORPION-xisa [38]

(-2,-3) is the answer to the first part

5 0

2 years ago

How to Solve: -5% < 100

Evgesh-ka [11]

Answhver:khglujlihluf