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Ilya [14]
4 years ago
7

Melissa purchased $39.46 in groceries at a store. The cashier gave her $1.46 in change from a $50 bill. How much change should t

he cashier have given Melissa?
Mathematics
1 answer:
AleksandrR [38]4 years ago
7 0

Answer:

$10.54

Step-by-step explanation:

Melissa purchased $39.46 in groceries at a store.

She gave the cashier a $50 bill.

Her Change = Total Amount Given - Cost of Purchased Goods

                    =50-39.46=$10.54

The Cashier should have given Melissa $10.54 instead of $1.46.

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Ms. Hanuanaer helped students prepare juice. The recipe was 320 ounces of cranberry juice, 320 ounces of sprite, and a splash of
salantis [7]
This is a two step word problem so first your gonna have to subtract 320-50= 270 then divide to find your final answer so 270 divided by 8 is 33.75
4 0
3 years ago
Choose all the quadratic pairs that are equivalent. 1 2 (x + 4)2 = 2 x2 + 8x + 15 = 0 (x − 5)2 = 1 x2 − 10x + 26 = 0 3(x − 1)2 +
Artemon [7]

Answer:

Only equation 1 and 2 are equal.

Step-by-step explanation:

2 (x + 4)2 = 2

2( x² + 8x+ 16) = 2               Applying the square formula

2x² + 16x+ 32 = 2

2x² + 16x+ 32 -2= 0

2x² + 16x+ 30 = 0

2( x² + 8x+ 15)= 0           Taking 2 as common

x2 + 8x + 15 = 0------------eq 1

x2 + 8x + 15 = 0-------------eq 2

(x − 5)2 = 1

x²-10x+25= 1             Applying the square formula

x²-10x+25- 1= 0

x²-10x+24= 0-------------eq 3

x2 − 10x + 26 = 0 -------------eq 4

3(x − 1)2 + 5 = 0

3( x²-2x+1)+5= 0               Applying the square formula

3x²-6x+3+5= 0

3x²-6x+ 8= 0-------------eq 5

3x2 − 6x + 8 =1

3x2 − 6x + 8 -1=0

3x2 − 6x + 7 =0-------------eq 6

3 0
3 years ago
- 6 = z + 3<br>solve each equation for the unknown variable​
Nataly [62]
Solution: Z= -9

Reasoning: -6 - 3 = -9
4 0
3 years ago
A cat eats 2/3 cup of food each day. How many days will a bag containing 16<br> cuns of food last?
Masja [62]

Answer:

The correct answer is 24

7 0
3 years ago
Solve.
Eva8 [605]

2x^2+x-1=2\ \ \ |-2\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\ \ |-3\\2x=-3\ \ \ |:2\\x=-\frac{3}{2}\\\\x-1=0\ \ \ |+1\\x=1

Answer: C 1, -3/2

4 0
3 years ago
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