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sesenic [268]
3 years ago
11

How to solve 0=-x-4 in Y=Mx+b

Mathematics
1 answer:
Ber [7]3 years ago
3 0

all you have to do is search it up on Google or ask your teacher or your in you can get your answer off of here so good night

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What is between 68 2/3 and 72 1/2
g100num [7]
We need answer choices
8 0
3 years ago
Read 2 more answers
A university employs a total of 560 teaching assistants and research assistants. There are three times as many teaching
Scrat [10]

Answer:

170

Step-by-step explanation:

There are three times as many teaching assistants as research assistants. Find the number of research assistants employed by the university. Hence the number of research assistants is 170.

8 0
2 years ago
The sides of a octagon each have a length of 8x inches.write an expression for the Perimeter of the octagon in inches
miss Akunina [59]

8(8x)

<em>I hope I helped you with your solution! If I did, please give me Brainliest, and click the "thanks" button! It would truly make my day!</em>

6 0
3 years ago
Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]
JulijaS [17]

Answer:

f_{avg}=\frac{1}{e-1}

Step-by-step explanation:

We are given that a function

f(x)=2lnx

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx

By Parts integration formula

\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx

u=ln x and v=dx

Apply by parts integration

f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))

f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})

f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}

By using property lne=1,ln 1=0

f_{avg}=\frac{1}{e-1}

8 0
3 years ago
Find the surface area of a right prism whose bases are equilateral triangles with side lengths of 6in. The height of the prism i
vesna_86 [32]

ANSWER

211.2 {in}^{2}

EXPLANATION

The surface area of a triangular prism is

equal to the area of two triangular faces

plus the area of the three rectangular faces.

The area of the equilateral triangle is calculated using the formula:

= 2 \times \frac{ \sqrt{3} }{4}  {s}^{2}  + 3 \times  \: bh

where s=6 is the length of one side.

and b=6 is the breadth of the rectangle and h=10 is the height of the rectangle.

Surface area

= 2 \times \frac{ \sqrt{3} }{4}  \times  {6}^{2}  + 3 \times  \: 6 \times 10

= 18\sqrt{3} + 180

=211.2square inches.

8 0
3 years ago
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