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alexira [117]
4 years ago
15

Rewrite the system of linear equations as a matrix equation AX = B.

Mathematics
1 answer:
Artemon [7]4 years ago
7 0

Answer:

Given:  \begin{bmatrix}2&5&-2&1&2\\1&1&-2&1&4\end{bmatrix}

2x_{1}+5 x_{2}  - 2_{3} + x_{4} + 2x_{5}\\[tex][tex]x_{1}+ x_{2}  - 2_{3} + x_{4} + 4x_{5}\\

The system of linear equations in matrix form may be written as:

AX=B,

where,

A is coefficient matrix of order 2\times 4 and is given by:

A = \begin{bmatrix}2&5&-2&1&2\\1&1&-2&1&4\end{bmatrix}

X is variable matrix of order  5\times 1 and is given by:

X=  \begin{bmatrix}x_{_{1}}\\x_{_{2}}\\x_{3}\\x_{4}\\x_{5}\end{bmatrix}

and B is the contant matrix of order 2\times 1 and is given by:

B = \begin{bmatrix}1\\5\end{bmatrix}

Now, AX=B

\begin{bmatrix}2&5&-2&1&2\\1&1&-2&1&4\end{bmatrix}. \begin{bmatrix}x_{_{1}}\\x_{_{2}}\\x_{3}\\x_{4}\\x_{5}\end{bmatrix} = \begin{bmatrix}1\\5\end{bmatrix}

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3 years ago
Simplified form of 4(12x+16)
Ierofanga [76]

Answer:

The given expression simplified is <em>48x + 64.</em>

Step-by-step explanation:

Solving this problem entails of simplifying the expression provided. We'll use the distributive law, or the distributive property, to write the expression in the simplest form.

Distributive law states:

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We know that...

  • a = 4
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Following the rules of distributive law, we can set up the expression to match this property.

a(b + c)  ⟶  4(12x + 16)  ⟶  (4 × 12x) + (4 × 16)

The expression will now be easier to simplify. Here, the last step would be to multiply the terms within the parentheses. Remember that we <u>cannot</u> multiply a number by a variable. When you multiply '4' by '12x', just multiply twelve and four, and leave the variable as is.

(4 × 12x) + (4 × 16)

48x + (4 × 16)

48x + 64

Think back on what I mentioned earlier about not being able to multiply a number by a variable. The same rule applies to adding two terms, in which one is a constant and the other consists of a coefficient <u>and variable</u>. Our simplified expression has '48x', which is a coefficient and variable, and '64', which is a constant. This means we cannot add these two terms together.

Our expression seems to be in the simplest form because no further actions can be taken. The correct answer should be <em>48x + 64.</em>

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The data represent the number of cans collected by different classes for a service
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Answer:

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HELP!!
Contact [7]

Answer:

Yes

Step-by-step explanation:

Statement                                         Reason

ab = bd                                               Given

ac=cd                                                  Given

bc = cb                                                definiton of reflex line

triangle abc is congruent to triangle dbc      side side side postulate

7 0
3 years ago
Read 2 more answers
Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t
katrin2010 [14]

Answer:

\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of \triangle ACD and the hypotenuse of \triangle ADB.

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is \angle CAD. The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}

Now use this value in the Law of Sines to find AD:

\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}

Recall that \sin 45^{\circ}=\frac{\sqrt{2}}{2} and \sin 60^{\circ}=\frac{\sqrt{3}}{2}:

AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}

Now that we have the length of AD, we can find the length of AB. The right triangle \triangle ADB is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio x:x\sqrt{3}:2x, where x is the side opposite to the 30 degree angle and 2x is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent 2x in this ratio and since AB is the side opposite to the 30 degree angle, it must represent x in this ratio (Derive from basic trig for a right triangle and \sin 30^{\circ}=\frac{1}{2}).

Therefore, AB must be exactly half of AD:

AB=\frac{1}{2}AD,\\AB=\frac{1}{2}\cdot 50\sqrt{6},\\AB=\frac{50\sqrt{6}}{2}=\boxed{25\sqrt{6}}\approx 61.24

3 0
3 years ago
Read 2 more answers
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