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Romashka [77]
3 years ago
7

Number has more than two factors

Mathematics
2 answers:
VMariaS [17]3 years ago
7 0
I'm going to assume that you are asking how a number can have two factors.
So, a factor is an integer (non-fractional/decimal number) you multiply by another integer to get the actual number.

Well, let's look at the number 4. The number four has the following factors:
1, 2, 4
In a 'rainbow' style, you match the two outer numbers, then the two next inner numbers, and so on.
Because the number '2' is the one in the center and there is no other number to multiply it by, it must multiply by itself to reach the number 4.
Well, you must have two numbers to actually multiply together, so every number has two factors: 1, and itself (except for 0). 
I hope this helps, and good luck :)

lisabon 2012 [21]3 years ago
3 0
4,6,8,10,12,14,16,18 and so on in that pattern does have 2 or more fators
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A box of national brand cornflakes is $2.09 for 12 ounces. A box of store label cornflakes is $3.09 for 20 ounces.
grin007 [14]

Answer:

A)

  • National brand cornflakes is 0.174 = .17/oz
  • Store label cornflakes is 0.514 = .15/oz

B) The larger box is cheaper per ounce.


C) 2.09 – .30 = 1.79 for 12 ounces. So than $1.79/12= .15/oz.

They  would both be the same so there would be no better deal.


4 0
3 years ago
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of t
PIT_PIT [208]
The probability of having a 17 is the number of ways of having 17 divided by the number of different possible outcomes.

Ways of having 17:

Die 1     Die 2     Die 3    sum
6            6            5          6+6+5 = 17
6            5            6          6+5+6 = 17
5            6            6          5+6+6 = 17

Those are the only 3 possibilities of having 17 (you can only loose 1 point).

The total number of outcomes are 6*6*6 = 216

So the chances (probability) to win is 3 / 216 = 1/72 = 0.0139 
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E2%20%5Cleft%28%20%5Csqrt%5B3%5D%7B%20%7Bx%7D%5E%7B2%7D%20%20%2B%20
Verizon [17]

If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

\displaystyle \int_a^b f(x) \, dx = b f(b) - a f(a) - \int_{f(a)}^{f(b)} f^{-1}(x) \, dx

Let f(x) = \sqrt{1 + x^3}. Compute the inverse:

f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}

and we immediately notice that f^{-1}(x+1)=\sqrt[3]{x^2+2x}.

So, we can write the given integral as

\displaystyle \int_0^2 f^{-1}(x+1) + f(x) \, dx

Splitting up terms and replacing x \to x-1 in the first integral, we get

\displaystyle \int_1^3 f^{-1}(x) \, dx + \int_0^2 f(x) \, dx = 2 f(2) - 0 f(0) = 2\times3+0\times1=\boxed{6}

7 0
1 year ago
I need the missing termmmmm
zepelin [54]

Answer:

6x^2

Step-by-step explanation:

The missing term is in the box that signifies the multiplication of the term 2x and the term 3x:

2x * 3x = 6x^2

8 0
2 years ago
Read 2 more answers
Work out<br><img src="https://tex.z-dn.net/?f=1%20%5Cfrac%7B2%7D%7B3%7D%20-%20%20%5Cfrac%7B11%7D%7B15%7D%20%20" id="TexFormula1"
zhuklara [117]

1\dfrac{2}{3}-\dfrac{11}{15}=1\dfrac{2\cdot5}{3\cdot5}-\dfrac{11}{15}=1\dfrac{10}{15}-\dfrac{11}{15}=\dfrac{25}{15}-\dfrac{11}{15}=\dfrac{14}{15}

6 0
3 years ago
Read 2 more answers
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