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3 years ago

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A set of symbols that expresses a mathematical rule is called a

2 answers:

Elenna [48]3 years ago

8 0

Answer:

A set of symbols that expresses a mathematical rule or principle; for example, the formula for the area of a rectangle is a = lw, where a is the area, l the length, and w the width. The American Heritage® Student Science Dictionary, Second Edition.

Step-by-step explanation:

Kamila [148]3 years ago

5 0

Answer:

A set of symbols that expresses a mathematical rule or principle; for example, the formula for the area of a rectangle is a = lw, where a is the area, l the length, and w the width.

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Write the following in ascending order a)4/10,49/100,357/10,1/1001 plz fast ,correct and plzz with explanation

suter [353]

Answer:

1/1001 < 4/10 < 49/100 < 357/10

Step-by-step explanation:

4/10 => 0.4

49/100 => 0.49

357/10 => 35.7

1/1001 => 0.0009

Ascending order is from smallest to the greatest.

5 0

3 years ago

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Alexxandr [17]

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3 years ago

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What is 50 minutes before 8:40 am

ale4655 [162]

7:50 am

60 minutes before 8:40 would be 7:40 so 10 minutes after that would be 7:50

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3 years ago

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If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

3 years ago

Help its due in 5 mins lol

inessss [21]

Y= 26 & x=35 hope I did it on time!

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3 years ago