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Fittoniya [83]
3 years ago
13

3, 5, 9, 15, 23, ___ whats the next number

Mathematics
2 answers:
swat323 years ago
5 0
The number/answer to this question is 33 because it is in pattern 3+2=5. 5+4=9. 9+6=15. 15+8=23. 23+10=33
Juliette [100K]3 years ago
5 0
3,5,9,15,23
The difference between number is a multiple of 2:
3-5 = 1x2
9-5 = 2x2
15-9=3x2
23-15=4x2
??-23= 5x2; ?? = 10+23 =33

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You have 3/4 of a pound of peanuts. You have 10 cupcakes . What fraction of nuts is in each cupcake
kvasek [131]

Each cupcake would have 3/40 of a pound of nuts since that is 10x smaller than the total they have so they could put that amount into 10 cupcakes.

The answer is 3/40

8 0
3 years ago
Find the slope of the line that passes through the points (0, -3) and (-4,1).
kozerog [31]

The formula for slope is \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

In this case:

y_{2} = 1\\ y_{1} }= -3\\x_{2} = -4\\x_{1} = 0

so...

\frac{1 - (-3)}{-4 - 0}

\frac{4}{-4}

-1 <<<The slope

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
3 years ago
Read 2 more answers
We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.
Juli2301 [7.4K]

Answer:

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

Null hypothesis:p\geq 0.8  

Alternative hypothesis:p < 0.8  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation  

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

\hat p=\frac{97}{110}=0.882 estimated proportion of students who completed the modules before class

p_o=0.8 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v{/tex} represent the p value (variable of interest)  2) Concepts and formulas to use  We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%:  Null hypothesis:[tex]p\geq 0.8  

Alternative hypothesis:p < 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

5 0
3 years ago
1 of 3
lara31 [8.8K]

Answer:

a

n

=

2

2

n

−

1

Step-by-step explanation:

hope this helps

3 0
3 years ago
What percent of 25 is 21?
Damm [24]
21 IS 84% OF 25!!!!!
8 0
3 years ago
Read 2 more answers
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