3 years ago

What are names for 8 &9????

Mathematics

1 answer:

melomori [17]3 years ago

3 0

8.) 121 over the square root of 121
9.) pie over 2

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Rationalize the denominator of the fraction and enter the new denominator below. 8/2-√12

Studentka2010 [4]

$\frac{8}{2-\sqrt{12}}=\frac{8}{2-\sqrt{4\cdot3}}=\frac{8}{2-2\sqrt3}=\frac{8}{2(1-\sqrt3)}=\frac{4}{1-\sqrt3}\\\\\frac{4}{1-\sqrt3}\cdot\frac{1+\sqrt3}{1+\sqrt3}=\frac{4(1+\sqrt3)}{1^2-(\sqrt3)^2}=\frac{4(1+\sqrt3)}{1-3}=\frac{4(1+\sqrt3)}{-2}=-2(1+\sqrt3)}\\\\=-2-2\sqrt3$

$if\ \frac{8}{2}-\sqrt{12}=4-\sqrt{4\cdot3}=4-2\sqrt3$

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2 years ago

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Taya2010 [7]

Answer:

a rectangular field.The length of rectangular field is three times the breadth of the field. If the area of the path is 500 m square ,then find the length and breadth

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2 years ago

Hey can you please help me posted picture of question

Debora [2.8K]

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = -11
a = coefficient of squared term = 2
c = constant term = 15

Using the values, we get:
$x= \frac{11+- \sqrt{121-4(2)(15)} }{2(2)} \\ \\ 
x= \frac{11+-1}{4} \\ \\ 
x=3, x= 2.5$

So, the correct answer to this question are option B and D

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3 years ago

Find the missing value so that the two points have a slope of -2.(1,y) and (6,-5)

Aloiza [94]

Answer:

(-5-y)/(6-1)= -2

(-5-y)/(5)= -2

-5-y=-10

-y = -5

y = 5

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storchak [24]

What the make no sense but I believe it is 50.24 hope that helps

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2 years ago