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alina1380 [7]
3 years ago
9

How to find the square root of 128

Mathematics
2 answers:
ra1l [238]3 years ago
4 0
11.31 just the square root button on a calculator  
mezya [45]3 years ago
4 0
   
\sqrt{128} =   \sqrt{64 \times 2} = \boxed{\bf 8 \sqrt{2} }



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Can u help me on this?
a_sh-v [17]

Answer:

B

Step-by-step explanation:

70-20=50

i don't sure correct or not

7 0
3 years ago
Given that f(x) = 2x2 − 96, find x.
NISA [10]
F(x)=2x(2)−96

Step 1: Add -4x to both sides.

xf+ −4x = 4x−96+ −4x

xf −4x= −96

Step 2: Factor out variable x.

x(f−4)= −96

Step 3: Divide both sides by f-4.

x(f−4)/ f−4 = −96/ f−4

x= −96/f−4

Answer:

x= −96/ f−4

3 0
3 years ago
Read 2 more answers
Simplify 16m6-15mn+m6+17mn​
tia_tia [17]

Answer:

17m^6 + 2mn

Step-by-step explanation:

16m^6 -15mn +m^6 + 17mn

Combine like terms, rewrite the equation and perform the operations between the coefficients,

16m^6 +m^6 -15mn+17mn

17m^6 + 2mn

3 0
2 years ago
Read 2 more answers
PLEASE HELP!!! Find the equation , in the standard form of the line passing through the points (3,-4) and (5,1)
ExtremeBDS [4]
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ 3 &,& -4~) 
%  (c,d)
&&(~ 5 &,& 1~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-4)}{5-3}\implies \cfrac{1+4}{5-3}\implies \cfrac{5}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=\cfrac{5}{2}(x-3)\implies y+4=\cfrac{5}{2}x-\cfrac{15}{2}

\bf y=\cfrac{5}{2}x-\cfrac{15}{2}-4\implies y=\cfrac{5}{2}x-\cfrac{23}{2}\impliedby 
\begin{array}{llll}
\textit{now let's multiply both}\\
\textit{sides by }\stackrel{LCD}{2}
\end{array}
\\\\\\
2(y)=2\left( \cfrac{5}{2}x-\cfrac{23}{2} \right)\implies 2y=5x-23\implies \stackrel{standard~form}{-5x+2y=-23}
\\\\\\
\textit{and if we multiply both sides by -1}\qquad 5x-2y=23

side note:  multiplying by the LCD of both sides is just to get rid of the denominators
5 0
3 years ago
A rectangular swimming pool that is 10ft wide bu 16ft long is surrounded bu a cement sidewalk of uniform width. If the area of t
Bess [88]

The width of the sidewalk would be 10ft.

Sorry if incorrect

6 0
3 years ago
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