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3 years ago

5

the sport field at patton elementryschool is shaped like a rectangle . the field is 72 yard lobg and 46 yardwide. what isthe are

a of the field in square yard

1 answer:

valina [46]3 years ago

6 0

Length x width will give you area so...

72 x 46 = 3,312 yards is the area

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The surface areas of two similar figures are 25 in2 and 36 in2. If the volume of the smaller figure is 250 in3, what is the volu

Slav-nsk [51]

Since the figures are similar, we can establish a rule of three as follows.
We know that the area of the smaller figure is $25in^{2}$ , and its volume is $250in^{3}$ . We also know that the area of the larger figure is $36in^{2}$ ; since we don't now its volume, lets represent it with $X$ :
$\frac{25in^{2}----\ \textgreater \ 250in^{3}}{36in^{2}----\ \textgreater \ Xin^{3}}$
$\frac{25}{36} = \frac{250}{X}$
$X= \frac{(250)(36)}{25}$
$X=360$

We can conclude that the volume of the larger figure is $360in^{3}$ ; therefore, the correct answer is a.

6 0

2 years ago

Read 2 more answers

A 20 cm long thin wire is used to form a square. What is the area of the square?

sergij07 [2.7K]

Answer:

25cm^2

Step-by-step explanation:

A square has 4 equal sides so each side will be 20/4 = 5cm

Easily calculate the area by taking 5 x 5 = 25cm^2

6 0

2 years ago

If tge angle at the center is 62° and the radius is 12 cm.. find the length of arc

insens350 [35]

Answer:

Step-by-step explanation:

r = 12 cm

Theta = 62

Length of arc = $\frac{theta}{360}*(2\pi r)$

$=\frac{62}{360}*2*3.14*12$

= 12.98 cm

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2 years ago

For the region bounded by y=2x, the x-axis, and x=1, determine which of the following is greater: the volume of the solid ge

telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

$\int\limits^1_0 {(pi)y^{2} } \, dx$

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

$\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy$

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0

2 years ago

Given f(x)=4x+5 and g(x)= x^2+x; find (f∘g)(-5)<br> Please show all steps thank you

Greeley [361]

Answer:

$(f\circ g)(-5)=85$

Step-by-step explanation:

We are given:

$\displaystyle f(x)=4x+5\text{ and } g(x)=x^2+x$

And we want to find:

$(f\circ g)(-5)$

This is equivalent to:

$\displaystyle =f(g(-5))$

So, we will evaluate g(-5) first, which yields:

$\displaystyle g(-5)=(-5)^2+(-5)=25-5=20$

So:

$=f(g(-5))=f(20)$

Then:

$\displaystyle f(20)=4(20)+5=80+5=85$

Therefore:

$(f\circ g)(-5)=85$

6 0

3 years ago