I think it’s A
Sorry if I’m wrong
Answer:
<h2>Area Semicircle = 1/2 πr² </h2>
where
r radius of semicircle
→ ½ * 22/7 * r² = 35
→ 11/7 * r² = 35
→ r² = 35*7/11
→ r² = 245/11
→ r² = 22.77
→ r = √22.77
→ r = 4.77
Therefore,
Diameter = 2*4.77
= 9.54 cm
The equation representing this situation would be 3 + 2x = c, where c is the total cost.
To find the cost to bring 12 dogs, you will replace the x with the number 12.
3 + 2 x 12 = 27
The cost would be $27.
-3/5 divided by 7/6 is -18/35
Current amount in account
P=36948.61
Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n
Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11
We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000
We can solve this by trial and error.
The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000. It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.
So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.
So it takes 15.00 years to reach the goal of 280000 years.
