Answer:
Snickerdoodles are 0.22$ each and chocolate chip are 0.43$ each
Step-by-step explanation:
using the information in the problem, you can make 2 separate equations: 8x+12y=6.92 and 5x+5y=3.25, let x= the cost of a snickerdoodle and y= the cost of a chocolate chip cookie.
With the 2 equations, we can isolate the y variable of the first equation and simplify which will give us y= -2/3x +6.92/12.
You can now take that equation and plug it into equation number 2:
5x+5(-2/3x + 6.92/12)=3.25.
solve that equation by multiplying 5 through the brackets: 5x-10/3x+34.6/12=3.25
add common terms: 5/3x=4.4/12
find the value of x, you will get x=0.22
plug the value of x (0.22) into one of your equations and solve for the y-value
Answer:
Olivia invested $2900 in a savings account that paid 4.5%/yr and $900 in a government bond that paid 5.5%/yr.
Step-by-step explanation:
With the information provided you can write the following equations:
x+y=3800 (1)
0.045x+0.055y=180 (2), where:
x is the amount invested in a savings account
y is the amount invested in a government bond
First, you can solve for x in (1):
x=3800-y (3)
Next, you can replace (3) in (2) and solve for y:
0.045(3800-y)+0.055y=180
171-0.045y+0.055y=180
0.01y=9
y=9/0.01
y=900
Finally, you can replace the value of y in (3) to find x:
x=3800-900
x=2900
According to this, the answer is that Olivia invested $2900 in a savings account that paid 4.5%/yr and $900 in a government bond that paid 5.5%/yr.
i. 5x ≥ -12 (It can be solved similarly to an equality)
5x/5 ≥ -12/5
x ≥ -12/5
The number line looks along the lines of
<---------l-------------> (filled circle)
-12/5
ii. The smallest integer that satisfies x ≥ -12/5 is -2 because -12/5 = -2.4.
The correct answer is A.
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Answer:
True
Step-by-step explanation:
I looked it up since I'm not good at explanations so here you go, sorry if this is a late reply;
"True: the product of two polynomials will be a polynomial regardless of the signs of the leading coefficients of the polynomials. When two polynomials are multiplied, each term of the first polynomial is multiplied by each term of the second polynomial."