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Vilka [71]
3 years ago
13

Create a function named first_a that uses a list comprehension. The function will take a single integer parameter n. Find every

number from 1 to n (inclusive) that is a multiple of 6 or a multiple of 11. Do not use a helper function.
Computers and Technology
1 answer:
aivan3 [116]3 years ago
3 0

Answer:

def first_a(n):

   lst1 =[x for x in range(1,n+1)if x%6==0 or x%11 ==0]

   print(lst1)

Explanation:

Above is a function in python programming language. We have used list comprehension to check numbers that are multiples of 6 or 11 in a range.

When this function is called it will receive an argument (n) of type integer, a range will then be generated from 1 to n+1 since n is inclusive. The modulo operator is used to determine is a value is a multiple of 6 or 11, since their multiples will evaluate to 0

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Write a program that replaces words in a sentence. The input begins with an integer indicating the number of word replacement pa
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Answer: provided in the explanation segment

Explanation:

This is the code to run the program:

CODE:  

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              original_String[i] = scan.next();

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          }

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          for (int i = 0; i < num_Of_Words; i++) {

              words_To_Replace[i] = scan.next();

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          int indx;

          for (int i = 0; i < num_Of_Words; i++) {

              indx = findWordInWordList(original_String, words_To_Replace[i], numInList);

              if (indx != -1)

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          }

          for (int i = 0; i < num_Of_Words; i++)

              System.out.print(words_To_Replace[i] + " ");

          System.out.println();

      scan.close();

      }

  }

cheers i hope this helps!!!!1

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