Question

) ^{2} - 5" alt="f(x) = (x + 3) ^{2} - 5" align="absmiddle" class="latex-formula">

Answer 1

Assuming that you want this simplified...

$f(x) = (x + 3)^2 - 5$

$--> = (x + 3)(x + 3) - 5$

Use the FOIL method and combine like terms:

$f(x) = (x^2 + 3x + 3x + 9) - 5$

$f(x) = x^2 + 6x + 9 - 5$

And your final answer is: $f(x) = x^2 + 6x + 4$