Answer:
see explanation
Step-by-step explanation:
given the 2 equations
y = x² - 2x - 19 → (1)
y + 4x = 5 → (2)
substitute y = x² - 2x - 19 into (2)
x² - 2x - 19 + 4x = 5 ( subtract 5 from both sides )
x² + 2x - 24 = 0 ← in standard form
(x + 6)(x - 4) = 0 ← in factored form
equate each factor to zero and solve for x
x + 6 = 0 ⇒ x = - 6
x - 4 = 0 ⇒ x = 4
substitute each value of x into (1) for corresponding y- coordinate
x = - 6 : y = (- 6)² - 2(- 6) - 19 = 36 + 12 - 19 = 29 ⇒ (- 6, 29)
x = 4 : y = 4² - 2(4) - 19 = 16 - 8 - 19 = - 11 ⇒ (4, - 11)
the solutions are (- 6, 29), (4, - 11)
Answer:
Full answer is in the media.Good luck.
To find the zeros of this equation you need to first set it equal to zero
2x2 + 16x - 9 = 0
But since you can't FOIL this equation you need to move the non-variable number over
2x2 +16x = 9
Now solve for x by pulling an x out of the equation
x(2x + 16) = 9
x = 9
2x +16 = 9
2x = -7
x = -7/2
So your zeros would be at x = 9, and -7/2
Answer:
Range: (2, 14)
General Formulas and Concepts:
<u>Algebra I</u>
- Range is the set of y-values that are outputted by function f(x)
Step-by-step explanation:
According to the graph, our line's y-values span from 2 to 14. Since both 2 and 14 are open dot, they are exclusive from the range:
Interval Notation: (2, 14)
Inequality Notation: 2 < y < 14
