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3 years ago

I really need some geometry help!

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

3 0

△RST≅△FED

HF is the side that needs to be congruent because that is the base of the triangle in both

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Simplify each expression -(5p+3)

aniked [119]

Answer:

-5p-3

Step-by-step explanation:

use the distributive property

8 0

2 years ago

The population of a city is 100,000. It doubles each decade for 5 decades. Select all

nikitadnepr [17]

Not sure but I think it’s C

5 0

2 years ago

Read 2 more answers

If a=-6 and b=-10 evaluate the following:<br>a + 6

ser-zykov [4K]

Answer:

-6+-10=-16

Step-by-step explanation:

+ - = -

........

6 0

2 years ago

Write a number in which the digit 3 is ten times the value of the digit 3 in 9.431

IgorC [24]

Answer:

Step-by-step explanation:

One number would be

9.31

The 3 in this number is 3/10

The 3 in the given number is 3/100

3/10 is 10 times bigger than 3/100

3/10 = 0.3

3/100 = 0.03

0.03 * x = 0.3 Divide both sides by 0.03

0.03/0.03 x = 0.3/0.03

x = 10

6 0

3 years ago

Harry is trying to solve the equation 0 = 2x2 − x − 6 using the quadratic formula. He has made an error in one of the steps belo

bija089 [108]

<h3><u>Given</u> - </h3>

➙ a quadratic equation in which Harry lagged due to an error made by him, 2x² - x - 6= 0

<h3><u>To solve</u> - </h3>

➙ the given quadratic equation.

<h3><u>Concept applied</u> - </h3>

➙ We will apply the quadratic formula as given in the question. So, let's study about quadratic equation first because we are supposed to apply the formula in equation.

What is quadratic equation?

➙ A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b, c are real numbers, a ≠ 0.

Now, what is quadratic formula?

➙The roots of a quadratic equation ax + bx + c = 0 are given by $\sf{\:\frac{-b \pm\: \sqrt {b ^ 2 - 4ac}}{2a}}$ provided b - 4ac ≥ 0.

<h3><u>Solution</u> - </h3>

here as per the given quadratic equation,

a = 2, b = -1 and c = -6

putting in the formula,

$\implies\sf{x=\frac{-(-1) \pm\: \sqrt {(-1)^2 - 4(2)(-6)}}{2(2)}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {1+48}}{4}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {49}}{4}}$

$\implies\sf{x=\frac{1 \pm\: 7}{4}}$

Solving one by one,

$\implies\sf{x=\frac{1 + \: 7}{4}}$

$\implies\sf{x=\frac{8}{4}}$

$\implies{\boxed{\bf{x=2}}}$

________________

$\implies\sf{x=\frac{1 - \: 7}{4}}$

$\implies\sf{x=\frac{-6}{4}}$

$\implies{\boxed{\bf{x=\frac{-3}{2}}}}$

________________________________

<em><u>Note</u> - Hey dear user!! You haven't provided the solution which was solved by Harry (A.T.Q). Please go through the solution as it will help you to find the error done by Harry.</em>

Hope it helps!! (:

4 0

2 years ago