Answer:
<h2>b) 50in, 48in, 14in</h2>
Step-by-step explanation:
If <em>a ≤ b < c</em><em> </em>form of a right side, then <em>a² + b² = c²</em>
a) 3ft, 6ft, 5ft
3² + 5² = 6²
9 + 25 = 36
34 = 36 <em>FALSE</em>
b) 50in, 48in, 14in
14² + 48² = 50²
196 + 2304 = 2500
2500 = 2500 <em>CORRECT :)</em>
c) 53m, 48m, 24m
24² + 48² = 53²
576 + 2304 = 2809
2880 = 2809 <em>FALSE</em>
d) 8cm, 17cm, 14cm
8² + 14² = 17²
64 + 196 = 289
260 = 289 <em>FALSE</em>
We can rewrite a cube root into a fractional index form.
So, we can rewrite:
![\sqrt[3]{m^{2}n^{5}} = (m^{2}n^{5})^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bm%5E%7B2%7Dn%5E%7B5%7D%7D%20%3D%20%28m%5E%7B2%7Dn%5E%7B5%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D)
To find the x-intercepts (there are two), set the numerator = to 0 and solve the resulting equation for x:
x^2 + x - 12 = 0
Factoring,
(x+4)(x-3) = 0. Thus, x = -4 and x = 3.
The denominator has no bearing here.
Answer:
3 books per box, 3 left over.
Step-by-step explanation:
Brian has 18 books, and he is packing them into 5 boxes. 18 is only divisible by 1, 3, 9, and 18.
1 x 5 = 5 books = 13 left over. Still enough to pack more books.
3 x 5 = 15 books = 3 left over. This is the answer, but let's check the others as well.
9 x 5 = 45 books. He doesn't have that many! He can't put 9 books in each box because it would only take 2 boxes he's using all 5.
18 x 5 = 90 books. We can clearly see this isn't the answer. He would only be able to put all 18 books in 1 box but he wants to use all 5 boxes.
There are 3 books in each box with 3 left over.
