It won't let me post. Please see the comments on this answer for the answer.
Answer:
Number 1 would be the answer and most safest one to choose.
Answer:
Starting from root, recursively traverse the min-heap. Once we find a key with value less than our X, we know that every key in subtree of that key will be also smaller than our X. Otherwise, we should keep traversing.
Explanation:
The complexity of this algorithm will be O(N) where N is the number of keys in our min-heap.
<span>Append parent suffixes of the primary DNS suffix is the appropriate option in the TCP/IP settings window that will allow the system to easily resolve the names in the mentioned namespaces. Name transfer is performed on the respective suffix when you select this option.</span>