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nordsb [41]
3 years ago
11

Please help me with this question ASAP Inequalities 9+3/5x>81/5

Mathematics
1 answer:
Goryan [66]3 years ago
5 0

Answer:

9+3/5x-(81/5)=0

Step-by-step explanation:

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Pls help me ima give BRAINLIST
andrey2020 [161]

Answer:

x = -2

Step-by-step explanation:

x = -2, is a vertical line, y = 5 is a horizontal line.

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4 years ago
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Line that is parallel to y= -3/2x-1
VLD [36.1K]

Answer:

See below.

Step-by-step explanation:

There is an infinite number of lines parallel to y = -3/2x - 1.

They have the same slope, -3/2, and a different y-intercept.

Examples:

y = -3/2x + 1

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6 0
3 years ago
The cost of 7/2 meters of clothes is $231/4. What is the cost of one meter of cloth?
klio [65]
First of all, i will start by comparing the given values. That will be;
7/2 meters=$231/4
     1 meter= x
  I represented the unknown value by x. Anyway, you have to cross and multiply. SO 7/2 multiplies x to give you 7/2x and 1 multiplies 231/4 to give you 231/4. That will be;
7/2x=231/4
  Divide the both sides by 7/2. 
   7/2x÷7/2=231/4÷7/2
   When dividing fractions, the division sign changes to a multiplication sign and the fraction on the right turns upside down. So;
x=231/4 x 2/7
x=231/14
x=$33/2.
 Hope i helped.

5 0
3 years ago
Can you tell me how to calculate R for below Matrix ?
scoray [572]

Answer:

The rank of the matrix is 3.

Step-by-step explanation:

Consider the prided information.

x=\begin{bmatrix}x_1\\ x_2\\ x_3\end{bmatrix}=\begin{bmatrix}9&2&6&5&8\\ 12&8&6&4&10\\ 3&4&0&2&1\end{bmatrix}

Reduce the matrix in row echelon form as shown:

R_1\:\leftrightarrow \:R_2\begin{bmatrix}12&8&6&4&10\\ 9&2&6&5&8\\ 3&4&0&2&1\end{bmatrix}\\

R_2\:\leftarrow \:R_2-\frac{3}{4}\cdot \:R_1\ and\ R_3\:\leftarrow \:R_3-\frac{1}{4}\cdot \:R_1\\\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&2&-\frac{3}{2}&1&-\frac{3}{2}\end{bmatrix}

R_3\:\leftarrow \:R_3+\frac{1}{2}\cdot \:R_2\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&0&-\frac{3}{4}&2&-\frac{5}{4}\end{bmatrix}

R_2\:\leftarrow \:R_2-\frac{3}{2}\cdot \:R_3\ and\ R_1\:\leftarrow \:R_1-6\cdot \:R_3\\\begin{bmatrix}12&8&0&20&0\\ 0&-4&0&6&-2\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}\\R_2\:\leftarrow \:-\frac{1}{4}\cdot \:R_2\ , \ R_1\:\leftarrow \:R_1-8\cdot \:R_2\ and\ \:R_1\:\leftarrow \frac{1}{12}\cdot \:R_1\\\begin{bmatrix}1&0&0&\frac{8}{3}&-\frac{1}{3}\\ 0&1&0&-\frac{3}{2}&\frac{1}{2}\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}

The rank of a matrix is the number of non zeros rows.

Thus, the rank of the matrix is 3.

6 0
3 years ago
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