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soldier1979 [14.2K]
3 years ago
8

PLS HELP , find the values of x,y, & z in the figure

Mathematics
1 answer:
blsea [12.9K]3 years ago
7 0

Answer:

In the picture above.

Step-by-step explanation:

First: I solved the right side to get y=93.

Second:calculate the triangle to get z=15.

Third: x=90.

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LuckyWell [14K]

Answer:

1)7.288 feet

2)11.6 feet

3)safe

4) 3.7 feet

5) ∅= tan^{-1}(1.5) = 56.31 degrees

6)∅1= tan^{-1}(2) = 63.43 degrees

  ∅2= tan^{-1}(1.2) = 50.19 degrees

Step-by-step explanation:

1) The door barn is rectangular in shape. The length is 9 feet and The angle between diagonal and side is 39 degrees.

Applying trigonometry,

tan(39) = \frac{opposite}{adjacent} = \frac{s}{9} = 0.809

Thus, s= (9)(0.809) = 7.288 feet

2) Applying pythagoras theorm,

   (Diagonal)^{2} = (9)^{2} + (7.288)^{2} =134.115

  Diagonal length (d) = 11.58 feet. Nearest tenth place = 11.6 feet

3) The length of ladder is 14 foot and height from ground is 13.5 feet.

Applying trigonometry,

sin(∅) =  \frac{opposite}{hypotenous} = \frac{13.5}{14} = 0.964

∅ = angle of elevation = sin^{-1}(0.964) = 74.57 ≈ 75 degrees.

Thus tractor can climb safely.

4)Applying, pythgoras theorm,

14^{2} = (13.5)^{2}  + x^{2}

x = \sqrt{14^{2}-(13.5)^{2}} = 3.708

Thus, ladder should be placed at distance 3.7 feet

5)Let angle of elevation be ∅.

  tan(∅) = \frac{30}{20} = 1.5

  ∅= tan^{-1}(1.5) = 56.31 degrees

6)After moving 5 feet closer to barn, Let angle of elevation for light near barn be ∅1 and for farther one be ∅2.

Thus,

tan(∅1) = \frac{30}{15} = 2

  ∅1= tan^{-1}(2) = 63.43 degrees

tan(∅2) = \frac{30}{25} = 1.2

  ∅2= tan^{-1}(1.2) = 50.19 degrees

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