Question

Suppose there are 2 routers in sequence between Host A and Host B, all of which use store-and-forward routing. What is the total end-to-end delay for a packet originating from Host A with destination Host B, under the following conditions.Each of the link transmission rates are 9.1 MbpsThe total distance from Host A to Host B along its path of transmisison is 161.2 kmThe speed of propagation through the transmission medium is is 2.7 x 108 m/sThe packet size is 4 KiB

Answer 1

Answer:

Check the explanation

Explanation:

Going by the question above,there are 2 routers in a sequence amid Host A and Host B and using store-and-forward routing.

So that time would conprise of both propagation delay and transmission time

Propagation delay is nothing but the time taken for traveling.

Transmission delay is the amount of delay time from the beginning to end of transmission)

Now,

Propagation delay = distance traveled / speed of propagation

= 161200 / 2.7 *108 = 59703703.70 * 10-8 mili sec

Transmission delay:

= packet size / bandwidth

= 4 / (9.1 * 1024) = 4.2925 * 10-1 mili sec

Let us assume routers have zero (0) processing time

total time = Transmission delay by host A + Transmssion delay by router1 + Transmssion delay by router2 + propagation time

= 3 * ( 4.2925 * 10-1 ) + (59703703.70 * 10-8)

= 1.28775 + 0.5970370370 ms

= 1.884787 ms