Ask question

Ask question

All categories

2 years ago

15

The sum of two numbers is 58.the smaller number is 12 less than the larger number.what are the numbers?

2 answers:

goldfiish [28.3K]2 years ago

4 0

Answer:

the larger number is 35 and the smaller one is 23

Step-by-step explanation:

I am Lyosha [343]2 years ago

3 0

Answer: smaller number is 23, larger number is 35

Step-by-step explanation:

Let the smaller number be y

The larger number will be y+12

The addition of the numbers is 58.

y+(y+12) = 58

y+y+12 = 58

2y+12 = 58

2y= 58-12

2y= 46

y= 46/2

y= 23

The smaller number is 23

Larger number will be 23+12=35

You might be interested in

Hola alguien sabe y me explique como puedo resolver esto me dice que use los numeros dados y que haga una familia de hechos para

VMariaS [17]

5+4=9 es uno 4+5=9 es Otro 9-5=4 es Otro 9-4=5

6 0

2 years ago

Scientists once thought that life spontaneously arose from nonliving things. It took extensive experimentation and the invention

tatiyna

A. Centrifuge had the biggest impact on the development of the cell theory

7 0

2 years ago

A bouncing rubber ball has each of the following except _____.

REY [17]

The answer is c heat

6 0

3 years ago

A carnival ride is in the shape of a wheel with a radius of 25 feet. The wheel has 20 cars attached to the center of the wheel.

Vladimir79 [104]

Centre angle will be 360° as its totally a circle.

radius=r=25ft

Angle between two cars=360/20=18°

Arc length=L

$\\ \sf\longmapsto L=\dfrac{\theta}{360}(2\pi r)$

$\\ \sf\longmapsto L=\dfrac{18}{360}(2\pi(25))$

$\\ \sf\longmapsto L=\dfrac{1}{20}(50\pi)$

$\\ \sf\longmapsto L=2.5\pi ft$

Now

Area be A

$\\ \sf\longmapsto A=\dfrac{1}{2}Lr^2$

$\\ \sf\longmapsto A=\dfrac{1}{2}(2.5\pi)(25)^2$

$\\ \sf\longmapsto A=625(2.5)\pi\dfrac{1}{2}$

$\\ \sf\longmapsto A=1562.5\pi/2$

$\\ \sf\longmapsto A=781\pi ft^2=$

4 0

2 years ago

If the 7th of an AP is equal to 11 times the 11th term, find the 18th term

Zina [86]

Answer:

-33 or 33

Step-by-step explanation:

The seventh term of an AP is written as:

$a + 6d$

The eleventh term of an AP is written as:

$a + 10d$

If the 7th term is 11 times the 11th term, then;

$a + 6d = 11(a + 10d)$

Expand to get:

$a + 6d = 11a + 110d$

$11a - a = 6d - 110d$

$10a = - 104d$

$\frac{a}{d} = - \frac{104}{10}$

$\frac{a}{d} = - \frac{52}{5}$

We must have a=-52 and d=5

Or

a=52 and d=-5

For the first case, the 18th term is :

$- 52 + 5 \times 17 = 33$

For the second case,

$52 - 5 \times17 = - 33$

3 0

3 years ago