4w^2+49=-28w solve for w
plz answer
1 answer:
Move all terms to one side
4w^2 + 49 + 28w = 0
Rewrite 4w^2 + 49 + 28w in the form a^2 + 2ab + b^2, where a = 2w and b = 7
(2w)^2 + 2(2w)(7) + 7^2 = 0
Use the Square of Sum: (a + b)^2 = a^2 + 2ab + b^2
(2w + 7)^2 = 0
Take the square root of both sides
3w + 7 = 0
Subtract 7 from both sides
2w = -7
Divide both sides by 2
<u>w = -7/2</u>
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Answer:
(-3,5)
Step-by-step explanation:
4x + 3y = 3
x − 3y = −18
Solve by addition/Elimination
x = -3
y = 5
So,
The solution of the system is (-3,5).
HELPPP PLZZ (I got you)
<u><em>Ace </em></u>
Answer: X is 15. N is 100
Answer:
c=4√2
Step-by-step explanation:
Sine the triangle is a right triangle you can use the Pythagorean theorem. a^2+b^2=c^2
(4)^2+(4)^2=c^2
16+16=c^2
32=c^2
c=√32
c=4√2
f + 0.2 =-3
f = -3 -0.2
f = -3.2
Answer:
Hellou our answer is 2/3
Step-by-step explanation:
5/8 ÷ 15/16 = 2/3
