3 years ago

4w^2+49=-28w solve for w plz answer

Mathematics

1 answer:

boyakko [2]3 years ago

3 0

Move all terms to one side

4w^2 + 49 + 28w = 0

Rewrite 4w^2 + 49 + 28w in the form a^2 + 2ab + b^2, where a = 2w and b = 7

(2w)^2 + 2(2w)(7) + 7^2 = 0

Use the Square of Sum: (a + b)^2 = a^2 + 2ab + b^2

(2w + 7)^2 = 0

Take the square root of both sides

3w + 7 = 0

Subtract 7 from both sides

2w = -7

Divide both sides by 2

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