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Trava [24]
2 years ago
15

Select the locations on the number line to plot the points 10/2 and -9 / 2​

Mathematics
1 answer:
Nat2105 [25]2 years ago
4 0

See in the picture below

<h2>Explanation:</h2>

A number line is a graph of a straight line that allows us to represent real numbers. So every point you write in this line represents a real number. Here we need to locate two points on the number line:

\frac{10}{2} \\ \\ -\frac{9}{2}

Let's write these numbers as:

\frac{10}{2}=5 \\ \\ -\frac{9}{2}=-4.5

So let's set 5 and -4.5 in the number line as shown below. As you can see 5 is located between 4 and 6 while -4.5 is located between -5 and -4.

<h2>Learn more:</h2>

Number line: brainly.com/question/2019837

#LearnWithBrainly

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Answer:

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Step-by-step explanation:

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Sec0 = -<img src="https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B12%7D" id="TexFormula1" title="\frac{13}{12}" alt="\frac{13}{12}" al
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Answer:

Solution given;

Sec θ=-\frac{13}{12}

cotθ< 0,

It lies in second quadrant.

where sin and cosec is positive.

Now

\frac{1}{cosθ}=-\frac{13}{12}

cosθ=\frac{12}{13}

\frac{b}{h}=\frac{12}{13}

b=12

h=13

By using Pythagoras law

p=\sqrt{13²-12²}=5

Now

exact values of tan θ=\frac{p}{b}=\frac{5}{12}

since it lies in II quadrant

<u>tan θ</u><u>=</u><u>-</u>\frac{5}{12}

and

sinθ=\frac{p}{h}=\frac{5}{13}

since it lies in II quadrant

<u>sin</u><u> </u><u>θ</u><u>=</u>\frac{5}{13}

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