The greatest common factor of

and

is
gcd(m*m*n*n, m*n*n*n) =m*n*n=

what we did, was to see how many m's and how many n's, each expression have, and then pick the smallest of each letter (factor).
the reason is that the common factor, must have enough m's and n's to divide the m's and n's of both expressions
so

also

thus, n is equal to 3
Answer: A)3
Answer:
Part A: L(-1,9) M(-4,3) N (-8,5)
Step-by-step explanation:
Subtract the amount used from the total packets:
5000 - 1824 = 3176 left after the first week.
3176 - 2352 = 824 total packets left.
Yes, every equilateral triangle is acute because the angles are always congruent(identical) and 60 degrees which is acute. But I may be wrong. :P
7+2=2+6 because 7+2=8 and 2+6 is = to 8 as well