Let's see what we can fill in here.
<ACE = 130
180 - 50 = 130
Now that we have two sides and an included angle, we can use the Law of Cosines.
Law of Cosines: c^2 = a^2 + b^2 - 2ab(cos(C))
Let's plug in what we know and solve!
c^2 = 40^2 + 38^2 - 2(40)(38)(cos(130))
R = 70.69706
Hope this helps!! :)
Answer:
(a - b)^2 = 49 - 4b^2 +2ab
Step-by-step explanation:
Given: a^2 + b^2 = 7b (assuming A is really “a”)
b^2 + (2b - a)^2 = 7^2
Find; (a - b)^2
Plan: Use Algebraic Manipulation
Start with b^2 + (2b - a)^2 = 7^2 =>
b^2 + 4b^2 - 4ab + a^2 = 49 by expanding the binomial.
a^2 + b^2 + 4b^2 - 4ab = 49 rearranging terms
a^2 + b^2 -2ab - 2ab + 4b^2 = 49 =>
a^2 - 2ab + b^2 = 49 - 4b^2 +2ab rearranging and subtracting 4b^2 and adding 2ab to both sides of the equation and by factoring a^2 - 2ab + b^2
(a - b)^2 = 49 - 4b^2 +2ab
Double Check: recalculated ✅ ✅
(a - b)^2 = 49 - 4b^2 +2ab
The independent variable would be hours spent working.
Answer:
Area is 582 feet squared
Step-by-step explanation:
So, it suggests you break the shape apart, which is exactly what we can do to solve this problem.
We know that the longest side is 38ft, but to find the remaining length of the top, we will subtract 21 from 38.
So: 38ft - 21ft = 17ft
Now we can break the shape. The square will be 21 by 18 ft, and the remaining rectangle shape will be 12 by 17ft.
For the area, we'll start with the square. The formula for area is length times width: A=LW
For the square, we have the length, 21, and the width 18ft. All we have to do is multiply them:
21 * 18 = 378ft. squared
Now we can move on the rectangle, which has a length of 17ft, and width of 12ft.
12 * 17 = 204ft. squared
Last step! We add our areas together to get the entire shape's area. So..
378ft. + 204ft. = 582ft. squared
Good luck :P
Answer:
Step-by-step explanation:
Simplify
