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galina1969 [7]
3 years ago
11

Can someone please answer this for me???

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0
$12.60 after 9 years started w/ $8
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Determine the equations of the vertical and horizontal asymptotes, if any, for g(x)=x-2/x^2+4x+3
KatRina [158]

Answer:

<h2>B. x = -1, x = -3, y = 0</h2>

Step-by-step explanation:

g(x)=\dfrac{x-2}{x^2+4x+3}\\\\vertical\ asymptote:\\\\x^2+4x+3=0\\x^2+x+3x+3=0\\x(x+1)+3(x+1)=0\\(x+1)(x+3)=0\iff x+1=0\ \vee\ x+3=0\\\\\boxed{x=-1\ \vee\ x=-3}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x-2}{x^2+4x+3}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(\frac{1}{x}-\frac{2}{x^2}\right)}{x^2\left(1+\frac{4}{x}+\frac{3}{x^2}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{\frac{1}{x}-\frac{2}{x^2}}{1+\frac{4}{x}+\frac{3}{x^2}}=\dfrac{0}{1}=0\\\\\boxed{y=0}

4 0
3 years ago
Using like terms simplify-k+2(-2k-5)
MrRa [10]

Answer:

-5k-10

Step-by-step explanation:

- k + 2 (- 2k - 5) = - k - 4k - 10 = - 5k - 10

5 0
3 years ago
. Let ????1 be the function that assigns to each nonnegative integer its last digit. Note: The nonnegative integers is the set o
zalisa [80]

The domain of a function is the complete set of possible values of the independent variable. In this case, the independent variable is any nonnegative integer. The nonnegative integers are the set of positive integers along with zero, then,

domain = {0, 1, 2, 3, ...} = natural numbers.

3 0
3 years ago
What is -1.2 × 0.4 plzz helpp​
sweet-ann [11.9K]

Answer:

It is -0.48

Step-by-step explanation:

8 0
3 years ago
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Ethan has 3 more than twice as many quarters as Francis. If they have 18 quarters altogether, how many quarters does Ethan have.
Lesechka [4]
15 quarters does Ethan posess! hope this helped.
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3 years ago
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