All categories

3 years ago

6+y= -3 what’s the answer

Mathematics

2 answers:

erma4kov [3.2K]3 years ago

7 0

Answer:

y=-9

Step-by-step explanation:

LenKa [72]3 years ago

7 0

Answer:

y=-9

Step-by-step explanation:

6+y= -3

Subtract 6 from each side

6+y-6 = -3-6

y=-9

You might be interested in

joe wants to purchase a new pair of basketball shoes that are on sale at two different stores. store a has the sale at 20% off.

yawa3891 [41]

Answer:

What is the question?

Step-by-step explanation:

4 0

3 years ago

Tina charges $94.50 for a job. How long did she babysit for?

Vlad [161]

Answer:

ima say 10 hours since its 9.45 hours she works.

8 0

3 years ago

Suppose y varies directly with x. If y = –20 when x = 2, find y when x = 14

Natasha_Volkova [10]

Answer:

y = -140

Step-by-step explanation:

Y varies directly with x

y = kx

We know y = -20 when x =2, we can solve for k

-20 = k*2

Divide each side by 2

-20/2= 2k/2

-10 =k

y = -10x

Now we want to find y when x = 14

y = -10 *14

y = -140

3 0

4 years ago

Read 2 more answers

102+900=1002 More. Then 100

Ksivusya [100]

Hello!

I don't exactly understand your question. If you mean to be asking whether or not 1002 is geater than 100, it is.

If you mean to be asking to add it: 102 + 900 + 100 = 1102

5 0

3 years ago

Read 2 more answers

Q(a+1) - 2q(a) if q(x) = x²+3x+4

siniylev [52]

$q(x) = {x}^{2} + 3x + 4$

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

$q(a) = {a}^{2} + 3a + 4$

Multiply sides by -2 :

$- 2q(a) = - 2( {a}^{2} + 3a + 4)$

$- 2q(a) = - 2 {a}^{2} - 6a - 8$

_________________________________

Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

$q(a + 1) = ({a + 1})^{2} + 3(a + 1) + 4 \\$

$q(a + 1) = {a}^{2} + 2a + 1 + 3a + 3 + 4 \\$

$q(a + 1) = {a}^{2} + 5a + 8$

_________________________________

Step (3)

$q(a + 1) - 2q(a) =$

${a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 = \\$

$- {a}^{2} - a = - a(a + 1)$

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

8 0

4 years ago