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solmaris [256]
3 years ago
12

1.

Mathematics
2 answers:
skad [1K]3 years ago
8 0

1 answer

weight of karen = k

weight of john = j

by the question

j=3k

then

case II

2j +k =875

2×3k+k=875

7k = 875

k=875/7

k=125

now

j=3k

=3×125

=375

hence john was 375 pound and karen was 125.

2 answer

let Mary be m and joes be j

by question

M=3J

CASE II

M + J=24

3J +J =24

J =24/4

J=6

NOW

M=3×6

M=18

Therefore Mary was 18 yrs old and Joes was 6 yrs old.

o-na [289]3 years ago
5 0

Answer 1...

j =3k

2j + k = 875

substituting the first eqn into the 2nd

2(3k) + k = 875

6k+ k =875

7k = 875

k =875/7 =125

thus j = 3(125) =375

Answer...2

m =3j

m+j = 24

3j +j= 24

4j= 24

joe= 6yrs

mary= 3(6) =18yrs

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ANEK [815]

Answer:

They charged <u>$6</u> for washing and <u>$2</u> for vacuuming the car.

Step-by-step explanation:

Let the charge of washing a car be 'x'.

And also let the charge of vacuuming a car be 'y'.

Now according to question, Trisha raised $38 washing 5 cars and vacuuming 4 cars.

So framing the above sentence in equation form, we get;

5x+4y=38\ \ \ \ \ equation\ 1

Again according to question, Byron raises $28 by washing 4 cars and vacuuming 2 cars.

So framing the above sentence in equation form, we get;

4x+2y=28\ \ \ \ \ equation\2

Now multiplying equation 2 by '2', we get;

2(4x+2y)=28\times2\\\\8x+4y=56\ \ \ \ equation\ 3

Now we subtract equation 1 from equation 3 and get;

(8x+4y)-(5x+4y)=56-38\\\\8x+4y-5x-4y=18\\\\3x=18\\\\x=\frac{18}{3}=6

Now substituting the value of 'x' in equation 1, we get;

5x+4y=38\\\\5\times6+4y=38\\\\30+4y=38\\\\4y=38-30=8\\\\y=\frac{8}{4}=2

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8 0
3 years ago
CAN SOMEBODY HELP ME PLEASE
Natasha_Volkova [10]

Answer:

  • vertex (3, -1)
  • y-intercept: (0, 8)
  • x-intercepts: (2, 0), (4, 0)

Step-by-step explanation:

You are being asked to read the coordinates of several points from the graph. Each set of coordinates is an (x, y) pair, where the first coordinate is the horizontal distance to the right of the y-axis, and the second coordinate is the vertical distance above the x-axis. The distances are measured according to the scales marked on the x- and y-axes.

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<h3>Vertex</h3>

The vertex is the low point of the graph. The graph is horizontally symmetrical about this point. On this graph, the vertex is (3, -1).

<h3>Y-intercept</h3>

The y-intercept is the point where the graph crosses the y-axis. On this graph, the y-intercept is (0, 8).

<h3>X-intercepts</h3>

The x-intercepts are the points where the graph crosses the x-axis. You will notice they are symmetrically located about the vertex. On this graph, the x-intercepts are (2, 0) and (4, 0).

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<em>Additional comment</em>

The reminder that these are "points" is to ensure that you write both coordinates as an ordered pair. We know the x-intercepts have a y-value of zero, for example, so there is a tendency to identify them simply as x=2 and x=4. This problem statement is telling you to write them as ordered pairs.

5 0
2 years ago
Which fraction is equal to k in the equation below? <br>1\3 / 2= k
Nitella [24]

Answer:

0_10 =0_2

Step-by-step explanation:

Convert the following to base 2:

0_10

Hint: | Starting with zero, raise 2 to increasingly larger integer powers until the result exceeds 0.

Determine the powers of 2 that will be used as the places of the digits in the base-2 representation of 0:

Power | \!\(\*SuperscriptBox[\(Base\), \(Power\)]\) | Place value

0 | 2^0 | 1

Hint: | The powers of 2 (in ascending order) are associated with the places from right to left.

Label each place of the base-2 representation of 0 with the appropriate power of 2:

Place | | | 2^0 |  

| | | ↓ |  

0_10 | = | ( | __ | )_(_2)

Hint: | Divide 0 by 2 and find the remainder. The remainder is the first digit.

Determine the value of 0 in base 2:

0/2=0 with remainder 0

Place | | | 2^0 |  

| | | ↓ |  

0_10 | = | ( | 0 | )_(_2)

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Answer:

b

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(x+12)^2=1

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ANSWER

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EXPLANATION

The complex number shown has coordinates (2,-2)

or

z = 2 - 2i

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|z|  =  \sqrt{ {2}^{2}  +  {( - 2)}^{2} }

|z|  =  \sqrt{ 8} = 2 \sqrt{2}

The argument is

\theta= \tan^{ - 1} ( \frac{ - 2}{2} )

\theta= \tan^{ - 1} ( -1) =  \frac{7\pi}{4}

The polar form is

2 \sqrt{2} ( \cos( \frac{7\pi}{4}   + i  \sin(  \frac{7\pi}{4} ) )

The first option is correct.

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4 years ago
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