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3 years ago

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Mary is saving money for college expenses. She saves the same amount each month. She saves the same amount each month. The table

shows the amount of money Mary has saved after 4 and 7 months. Which statements about the this situation are true and support the relationship as being proportional? Select all that apply.

1 answer:

marissa [1.9K]3 years ago

4 0

Answer:

A, C, D

Step-by-step explanation:

See attached for answer options

<u>As per the table, the points are:</u>

(4, 80) and (7, 140)

<u>This is linear function and the formula is:</u>

y = mx + b
m = (140-80)/(7-4) = 20
80 = 20*4 + b
b = 0

<u>So the function is</u>

y = 20x

<em>The correct answer options attached</em>

<em />

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Answer:

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Step-by-step explanation:

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Convert the whole number 1 into a fraction with denominator 4:

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As all the denominators are the same, we can simply add the numerators:

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2 years ago

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Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind

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Answer:

(a)

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

(b)

i.

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ii.

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iii.

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Step-by-step explanation:

Given

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$B = Boys$

$G = Girls$

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

And the number of elements are:

$n(S) = 8$

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

$1\ girl = \{GBB, BBG, BGB\}$

And the number of the list is;

$n(1\ girl) = 3$

The probability is calculated as;

$P(1\ girl) = \frac{n(1\ girl)}{n(S)}$

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$P(1\ girl) = 0.375$

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

$Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}$

And the number of the list is;

$n(Atleast\ 2 \ girls) = 4$

The probability is calculated as;

$P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}$

$P(Atleast\ 2 \ girls) = \frac{4}{8}$

$P(Atleast\ 2 \ girls) = 0.5$

Solving (biii) No girl

From the list of possible elements, we have:

$No\ girl = \{BBB\}$

And the number of the list is;

$n(No\ girl) = 1$

The probability is calculated as;

$P(No\ girl) = \frac{n(No\ girl)}{n(S)}$

$P(No\ girl) = \frac{1}{8}$

$P(No\ girl) = 0.125$

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Step-by-step explanation:

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Step-by-step explanation:

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